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Formula
Calculate the value
Answer
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$6 \sqrt{ 2 } \times \dfrac{ \sqrt{ 2 } }{ 2 }$
$6$
Calculate the value
$\color{#FF6800}{ 6 } \sqrt{ \color{#FF6800}{ 2 } } \color{#FF6800}{ \times } \color{#FF6800}{ \dfrac { \sqrt{ 2 } } { 2 } }$
$ $ Arrange the terms multiplied by fractions $ $
$\color{#FF6800}{ \dfrac { 6 \sqrt{ 2 } \sqrt{ 2 } } { 2 } }$
$\color{#FF6800}{ \dfrac { 6 \sqrt{ 2 } \sqrt{ 2 } } { 2 } }$
$ $ Reduce the fraction $ $
$\color{#FF6800}{ 3 } \sqrt{ \color{#FF6800}{ 2 } } \sqrt{ \color{#FF6800}{ 2 } }$
$\color{#FF6800}{ 3 } \sqrt{ \color{#FF6800}{ 2 } } \sqrt{ \color{#FF6800}{ 2 } }$
$ $ Simplify the expression $ $
$\color{#FF6800}{ 6 }$
Solution search results
search-thumbnail-Which of the following rational numbers are 
equivalent? 
$0Ptionsy$ 
A \frac{5}{6}, \frac{30}{36} 
B $s\sqrt{rac\left(} -2\right)\left(3\right)\sqrt{1rac} \sqrt{4\right)16\right)4} $ 
C $s\sqrt{11aC\left(} -4\right)1-7b,\sqrt{1rac\left(16\sqrt{35\right)9} } $ 
D \frac{1}{2},\frac{3}{8}
7th-9th grade
Other
search-thumbnail-The rationalizing factor of \sqrt{23} is 
$°$ $Options^{°}$ $0$ 
A 24 
23 
C \sqrt{23} 
D None of these
7th-9th grade
Other
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