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Formula
Multiply two numbers
Answer
Find the number of divisors
Answer
List all divisors
Answer
Do prime factorization
Answer
Organize using the law of exponent
Answer
$5 \times 5$
$25$
Multiply two numbers
$\color{#FF6800}{ 5 } \color{#FF6800}{ \times } \color{#FF6800}{ 5 }$
$ $ Multiply $ 5 $ and $ 5$
$\color{#FF6800}{ 25 }$
$3$
Find the number of divisors
$\color{#FF6800}{ 5 } \color{#FF6800}{ \times } \color{#FF6800}{ 5 }$
$ $ Do prime factorization $ $
$\color{#FF6800}{ 5 } \color{#FF6800}{ \times } \color{#FF6800}{ 5 }$
$\color{#FF6800}{ 5 } \times 5$
$ $ If the exponent is omitted, the exponent of that term is equal to 1 $ $
$\color{#FF6800}{ 5 } ^ { \color{#FF6800}{ 1 } } \times 5$
$5 ^ { 1 } \times \color{#FF6800}{ 5 }$
$ $ If the exponent is omitted, the exponent of that term is equal to 1 $ $
$5 ^ { 1 } \times \color{#FF6800}{ 5 } ^ { \color{#FF6800}{ 1 } }$
$\color{#FF6800}{ 5 } ^ { \color{#FF6800}{ 1 } } \times \color{#FF6800}{ 5 } ^ { \color{#FF6800}{ 1 } }$
$ $ Add the exponent as the base is the same $ $
$\color{#FF6800}{ 5 } ^ { \color{#FF6800}{ 1 } \color{#FF6800}{ + } \color{#FF6800}{ 1 } }$
$5 ^ { \color{#FF6800}{ 1 } \color{#FF6800}{ + } \color{#FF6800}{ 1 } }$
$ $ Add $ 1 $ and $ 1$
$5 ^ { \color{#FF6800}{ 2 } }$
$\color{#FF6800}{ 5 } ^ { \color{#FF6800}{ 2 } }$
$ $ Find the number of divisors using an exponent $ $
$\color{#FF6800}{ 3 }$
$1 , 5 , 25$
Find all divisors
$\color{#FF6800}{ 5 } \color{#FF6800}{ \times } \color{#FF6800}{ 5 }$
$ $ Do prime factorization $ $
$\color{#FF6800}{ 5 } \color{#FF6800}{ \times } \color{#FF6800}{ 5 }$
$\color{#FF6800}{ 5 } \times 5$
$ $ If the exponent is omitted, the exponent of that term is equal to 1 $ $
$\color{#FF6800}{ 5 } ^ { \color{#FF6800}{ 1 } } \times 5$
$5 ^ { 1 } \times \color{#FF6800}{ 5 }$
$ $ If the exponent is omitted, the exponent of that term is equal to 1 $ $
$5 ^ { 1 } \times \color{#FF6800}{ 5 } ^ { \color{#FF6800}{ 1 } }$
$\color{#FF6800}{ 5 } ^ { \color{#FF6800}{ 1 } } \times \color{#FF6800}{ 5 } ^ { \color{#FF6800}{ 1 } }$
$ $ Add the exponent as the base is the same $ $
$\color{#FF6800}{ 5 } ^ { \color{#FF6800}{ 1 } \color{#FF6800}{ + } \color{#FF6800}{ 1 } }$
$5 ^ { \color{#FF6800}{ 1 } \color{#FF6800}{ + } \color{#FF6800}{ 1 } }$
$ $ Add $ 1 $ and $ 1$
$5 ^ { \color{#FF6800}{ 2 } }$
$\color{#FF6800}{ 5 } ^ { \color{#FF6800}{ 2 } }$
$ $ List divisors of factors $ $
$\color{#FF6800}{ 5 } ^ { \color{#FF6800}{ 0 } } , \color{#FF6800}{ 5 } ^ { \color{#FF6800}{ 1 } } , \color{#FF6800}{ 5 } ^ { \color{#FF6800}{ 2 } }$
$\color{#FF6800}{ 5 } ^ { \color{#FF6800}{ 0 } } , \color{#FF6800}{ 5 } ^ { \color{#FF6800}{ 1 } } , \color{#FF6800}{ 5 } ^ { \color{#FF6800}{ 2 } }$
$ $ Calculate the product of all divisors $ $
$\color{#FF6800}{ 1 } , \color{#FF6800}{ 5 } , \color{#FF6800}{ 25 }$
$5 ^ { 2 }$
Organize using the law of exponent
$\color{#FF6800}{ 5 } \times 5$
$ $ If the exponent is omitted, the exponent of that term is equal to 1 $ $
$\color{#FF6800}{ 5 } ^ { \color{#FF6800}{ 1 } } \times 5$
$5 ^ { 1 } \times \color{#FF6800}{ 5 }$
$ $ If the exponent is omitted, the exponent of that term is equal to 1 $ $
$5 ^ { 1 } \times \color{#FF6800}{ 5 } ^ { \color{#FF6800}{ 1 } }$
$\color{#FF6800}{ 5 } ^ { \color{#FF6800}{ 1 } } \times \color{#FF6800}{ 5 } ^ { \color{#FF6800}{ 1 } }$
$ $ Add the exponent as the base is the same $ $
$\color{#FF6800}{ 5 } ^ { \color{#FF6800}{ 1 } \color{#FF6800}{ + } \color{#FF6800}{ 1 } }$
$5 ^ { \color{#FF6800}{ 1 } \color{#FF6800}{ + } \color{#FF6800}{ 1 } }$
$ $ Add $ 1 $ and $ 1$
$5 ^ { \color{#FF6800}{ 2 } }$
$5 ^ { 2 }$
Organize using the law of exponent
$\color{#FF6800}{ 5 } \times 5$
$ $ If the exponent is omitted, the exponent of that term is equal to 1 $ $
$\color{#FF6800}{ 5 } ^ { \color{#FF6800}{ 1 } } \times 5$
$5 ^ { 1 } \times \color{#FF6800}{ 5 }$
$ $ If the exponent is omitted, the exponent of that term is equal to 1 $ $
$5 ^ { 1 } \times \color{#FF6800}{ 5 } ^ { \color{#FF6800}{ 1 } }$
$\color{#FF6800}{ 5 } ^ { \color{#FF6800}{ 1 } } \times \color{#FF6800}{ 5 } ^ { \color{#FF6800}{ 1 } }$
$ $ Add the exponent as the base is the same $ $
$\color{#FF6800}{ 5 } ^ { \color{#FF6800}{ 1 } \color{#FF6800}{ + } \color{#FF6800}{ 1 } }$
$5 ^ { \color{#FF6800}{ 1 } \color{#FF6800}{ + } \color{#FF6800}{ 1 } }$
$ $ Add $ 1 $ and $ 1$
$5 ^ { \color{#FF6800}{ 2 } }$
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