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Formula
Solve a quadratic inequality
Answer
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Graph
$4 x ^ { 2 } - 4 x + 1 > 0$
$4 x ^ { 2 } - 4 x + 1 > 0$
Solution of inequality
$x < \dfrac { 1 } { 2 } \text{ or } x > \dfrac { 1 } { 2 }$
$4x ^{ 2 } -4x+1 > 0$
$x < \dfrac { 1 } { 2 } $ or $ x > \dfrac { 1 } { 2 }$
$ $ Solve a solution to $ x$
$\color{#FF6800}{ 4 } \color{#FF6800}{ x } ^ { \color{#FF6800}{ 2 } } \color{#FF6800}{ - } \color{#FF6800}{ 4 } \color{#FF6800}{ x } \color{#FF6800}{ + } \color{#FF6800}{ 1 } > 0$
$ $ Factorize the expression $ $
$\left ( \color{#FF6800}{ 2 } \color{#FF6800}{ x } \color{#FF6800}{ - } \color{#FF6800}{ 1 } \right ) ^ { \color{#FF6800}{ 2 } } > 0$
$\left ( \color{#FF6800}{ 2 } \color{#FF6800}{ x } \color{#FF6800}{ - } \color{#FF6800}{ 1 } \right ) ^ { \color{#FF6800}{ 2 } } > \color{#FF6800}{ 0 }$
$ $ Solve a solution to $ x$
$\color{#FF6800}{ x } < \color{#FF6800}{ \dfrac { 1 } { 2 } } $ or $ \color{#FF6800}{ x } > \color{#FF6800}{ \dfrac { 1 } { 2 } }$
$ $ 그래프 보기 $ $
Inequality
Solution search results
search-thumbnail-$1$ $x^{2}-9x+8\geq 0$ 
$2$ $x^{2}-4x+3=0$ 
$2$ $x^{2}-4x+3>0$ 
$4$ $x^{2}-12x<-20$ 
$5$ $x^{2}-6x-16>0$
7th-9th grade
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