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Formula
Factorize the expression
Answer
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$4c ^{ 2 } -1$
$\left ( 2 c - 1 \right ) \left ( 2 c + 1 \right )$
Arrange the expression in the form of factorization..
$\color{#FF6800}{ 4 } \color{#FF6800}{ c } ^ { \color{#FF6800}{ 2 } } \color{#FF6800}{ - } \color{#FF6800}{ 1 }$
$ $ Factorize to use the polynomial formula of sum and difference $ $
$\left ( \color{#FF6800}{ 2 } \color{#FF6800}{ c } \color{#FF6800}{ + } \color{#FF6800}{ 1 } \right ) \left ( \color{#FF6800}{ 2 } \color{#FF6800}{ c } \color{#FF6800}{ - } \color{#FF6800}{ 1 } \right )$
$\left ( \color{#FF6800}{ 2 } \color{#FF6800}{ c } \color{#FF6800}{ + } \color{#FF6800}{ 1 } \right ) \left ( \color{#FF6800}{ 2 } \color{#FF6800}{ c } \color{#FF6800}{ - } \color{#FF6800}{ 1 } \right )$
$ $ Sort the factors $ $
$\left ( \color{#FF6800}{ 2 } \color{#FF6800}{ c } \color{#FF6800}{ - } \color{#FF6800}{ 1 } \right ) \left ( \color{#FF6800}{ 2 } \color{#FF6800}{ c } \color{#FF6800}{ + } \color{#FF6800}{ 1 } \right )$
Solution search results
search-thumbnail-$3.$ $\left(3c^{3}-14c^{2}-22c+70\right)\div \left(3c+7\right)$ 
$Quotient$ 
$Remainder$ $\dfrac {\left(3c^{3}-14c^{2}-22c+70=} {3c+7}$
10th-13th grade
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