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Solve the inequality
Answer
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Graph
$4 - x \leq 5 \left ( x + 2 \right )$
$4 - x \leq 5 \left ( x + 2 \right )$
Solution of inequality
$x \geq - 1$
$4-x \leq 5 \left( x+2 \right)$
$x \geq - 1$
$ $ Solve a solution to $ x$
$4 - x \leq \color{#FF6800}{ 5 } \left ( \color{#FF6800}{ x } \color{#FF6800}{ + } \color{#FF6800}{ 2 } \right )$
$ $ Multiply each term in parentheses by $ 5$
$4 - x \leq \color{#FF6800}{ 5 } \color{#FF6800}{ x } \color{#FF6800}{ + } \color{#FF6800}{ 5 } \color{#FF6800}{ \times } \color{#FF6800}{ 2 }$
$4 - x \leq 5 x + \color{#FF6800}{ 5 } \color{#FF6800}{ \times } \color{#FF6800}{ 2 }$
$ $ Multiply $ 5 $ and $ 2$
$4 - x \leq 5 x + \color{#FF6800}{ 10 }$
$\color{#FF6800}{ 4 } \color{#FF6800}{ - } \color{#FF6800}{ x } \leq 5 x + 10$
$ $ Organize the expression $ $
$\color{#FF6800}{ - } \color{#FF6800}{ x } \color{#FF6800}{ + } \color{#FF6800}{ 4 } \leq 5 x + 10$
$- x + 4 \leq \color{#FF6800}{ 5 } \color{#FF6800}{ x } + 10$
$ $ Move the variable to the left-hand side and change the symbol $ $
$- x + 4 \color{#FF6800}{ - } \color{#FF6800}{ 5 } \color{#FF6800}{ x } \leq 10$
$- x \color{#FF6800}{ + } \color{#FF6800}{ 4 } - 5 x \leq 10$
$ $ Move the constant to the right side and change the sign $ $
$- x - 5 x \leq 10 \color{#FF6800}{ - } \color{#FF6800}{ 4 }$
$\color{#FF6800}{ - } \color{#FF6800}{ x } \color{#FF6800}{ - } \color{#FF6800}{ 5 } \color{#FF6800}{ x } \leq 10 - 4$
$ $ Organize the expression $ $
$\color{#FF6800}{ - } \color{#FF6800}{ 6 } \color{#FF6800}{ x } \leq 10 - 4$
$- 6 x \leq \color{#FF6800}{ 10 } \color{#FF6800}{ - } \color{#FF6800}{ 4 }$
$ $ Subtract $ 4 $ from $ 10$
$- 6 x \leq \color{#FF6800}{ 6 }$
$\color{#FF6800}{ - } \color{#FF6800}{ 6 } \color{#FF6800}{ x } \leq \color{#FF6800}{ 6 }$
$ $ Change the symbol of the inequality of both sides, and reverse the symbol of the inequality to the opposite direction $ $
$6 x \geq - 6$
$\color{#FF6800}{ 6 } \color{#FF6800}{ x } \geq \color{#FF6800}{ - } \color{#FF6800}{ 6 }$
$ $ Divide both sides by the same number $ $
$\color{#FF6800}{ x } \geq \color{#FF6800}{ - } \color{#FF6800}{ 1 }$
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