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Solve the equation
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$4 - \left ( 3 x - \left ( 5 x - y \right ) + 1 \right ) = 3$
$x$Intercept
$\left ( 0 , 0 \right )$
$y$Intercept
$\left ( 0 , 0 \right )$
$4- \{ 3x- \left( 5x-y \right) +1 \} = 3$
$x = \dfrac { 1 } { 2 } y$
$ $ Solve a solution to $ x$
$4 - \left ( 3 x \color{#FF6800}{ - } \left ( \color{#FF6800}{ 5 } \color{#FF6800}{ x } \color{#FF6800}{ - } \color{#FF6800}{ y } \right ) + 1 \right ) = 3$
$ $ Change the symbol of each term in parentheses when there is a (-) symbol in front of parentheses $ $
$4 - \left ( 3 x \color{#FF6800}{ - } \color{#FF6800}{ 5 } \color{#FF6800}{ x } + \color{#FF6800}{ y } + 1 \right ) = 3$
$4 - \left ( \color{#FF6800}{ 3 } \color{#FF6800}{ x } \color{#FF6800}{ - } \color{#FF6800}{ 5 } \color{#FF6800}{ x } + y + 1 \right ) = 3$
$ $ Calculate between similar terms $ $
$4 - \left ( \color{#FF6800}{ - } \color{#FF6800}{ 2 } \color{#FF6800}{ x } + y + 1 \right ) = 3$
$4 \color{#FF6800}{ - } \left ( \color{#FF6800}{ - } \color{#FF6800}{ 2 } \color{#FF6800}{ x } \color{#FF6800}{ + } \color{#FF6800}{ y } \color{#FF6800}{ + } \color{#FF6800}{ 1 } \right ) = 3$
$ $ Change the symbol of each term in parentheses when there is a (-) symbol in front of parentheses $ $
$4 + \color{#FF6800}{ 2 } \color{#FF6800}{ x } \color{#FF6800}{ - } \color{#FF6800}{ y } \color{#FF6800}{ - } \color{#FF6800}{ 1 } = 3$
$\color{#FF6800}{ 4 } + 2 x - y \color{#FF6800}{ - } \color{#FF6800}{ 1 } = 3$
$ $ Subtract $ 1 $ from $ 4$
$\color{#FF6800}{ 3 } + 2 x - y = 3$
$\color{#FF6800}{ 3 } + 2 x \color{#FF6800}{ - } \color{#FF6800}{ y } = 3$
$ $ Move the rest of the expression except $ x $ term to the right side and replace the sign $ $
$2 x = y$
$\color{#FF6800}{ 2 } \color{#FF6800}{ x } = \color{#FF6800}{ y }$
$ $ Divide both sides by the same number $ $
$\color{#FF6800}{ x } = \color{#FF6800}{ y } \color{#FF6800}{ \div } \color{#FF6800}{ 2 }$
$x = y \color{#FF6800}{ \div } \color{#FF6800}{ 2 }$
$ $ Convert division to multiplication $ $
$x = y \color{#FF6800}{ \times } \color{#FF6800}{ \dfrac { 1 } { 2 } }$
$x = \color{#FF6800}{ y } \color{#FF6800}{ \times } \color{#FF6800}{ \dfrac { 1 } { 2 } }$
$ $ Simplify the expression $ $
$x = \color{#FF6800}{ \dfrac { 1 } { 2 } } \color{#FF6800}{ y }$
$y = 2 x$
$ $ Solve a solution to $ y$
$4 - \left ( 3 x \color{#FF6800}{ - } \left ( \color{#FF6800}{ 5 } \color{#FF6800}{ x } \color{#FF6800}{ - } \color{#FF6800}{ y } \right ) + 1 \right ) = 3$
$ $ Change the symbol of each term in parentheses when there is a (-) symbol in front of parentheses $ $
$4 - \left ( 3 x \color{#FF6800}{ - } \color{#FF6800}{ 5 } \color{#FF6800}{ x } + \color{#FF6800}{ y } + 1 \right ) = 3$
$4 - \left ( \color{#FF6800}{ 3 } \color{#FF6800}{ x } \color{#FF6800}{ - } \color{#FF6800}{ 5 } \color{#FF6800}{ x } + y + 1 \right ) = 3$
$ $ Calculate between similar terms $ $
$4 - \left ( \color{#FF6800}{ - } \color{#FF6800}{ 2 } \color{#FF6800}{ x } + y + 1 \right ) = 3$
$4 \color{#FF6800}{ - } \left ( \color{#FF6800}{ - } \color{#FF6800}{ 2 } \color{#FF6800}{ x } \color{#FF6800}{ + } \color{#FF6800}{ y } \color{#FF6800}{ + } \color{#FF6800}{ 1 } \right ) = 3$
$ $ Change the symbol of each term in parentheses when there is a (-) symbol in front of parentheses $ $
$4 + \color{#FF6800}{ 2 } \color{#FF6800}{ x } \color{#FF6800}{ - } \color{#FF6800}{ y } \color{#FF6800}{ - } \color{#FF6800}{ 1 } = 3$
$\color{#FF6800}{ 4 } + 2 x - y \color{#FF6800}{ - } \color{#FF6800}{ 1 } = 3$
$ $ Subtract $ 1 $ from $ 4$
$\color{#FF6800}{ 3 } + 2 x - y = 3$
$\color{#FF6800}{ 3 } \color{#FF6800}{ + } \color{#FF6800}{ 2 } \color{#FF6800}{ x } - y = 3$
$ $ Move the rest of the expression except $ y $ term to the right side and replace the sign $ $
$- y = - \left ( 2 x \right )$
$- y = \color{#FF6800}{ - } \left ( \color{#FF6800}{ 2 } \color{#FF6800}{ x } \right )$
$ $ Organize the expression $ $
$- y = \color{#FF6800}{ - } \color{#FF6800}{ 2 } \color{#FF6800}{ x }$
$\color{#FF6800}{ - } \color{#FF6800}{ y } = \color{#FF6800}{ - } \color{#FF6800}{ 2 } \color{#FF6800}{ x }$
$ $ Change the sign of both sides of the equation $ $
$y = 2 x$
$ $ 그래프 보기 $ $
Graph
Solution search results
search-thumbnail-If the sum of two consecutive 
numbers is $45$ and one number is $X$ 
.This statement in the form of 
equation $1s:$ 
$\left(1$ Point) $\right)$ 
$○5x+1$ $1eft\left(x+1$ $r1gnt\right)=45s$ 
$○sx+1ef\left(x+2$ $r1gnt\right)=145s$ 
$sx+1x=45s$
7th-9th grade
Algebra
search-thumbnail-$s|ef\left(-1n$ $\left($ }\right)^{50}\ $\right)$ \ | | is\ equal\ to\ $S$ 
$s1S$ 
$S-1S$ 
$s2S$ 
$s50s$
7th-9th grade
Other
search-thumbnail-Given the set of ordered pairs $\left(\left(-7.0\right),\left(-6,5\right),\left(-5,-3\right),\left(-1,2\right)$ $\left(1,6\right),\left(2,-2\right)$ $\left(5,3\right)\left(7,-8\right)\right)$ 
Find f(7)fAleft(7\right) 
O a 
O b -8 
6. 
$5$
7th-9th grade
Algebra
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