App Store
Google PlayCalculator search results
Solve the equation
Answer
Graph
$y = 4 + x$
$y = 5$
$x$Intercept
$\left ( - 4 , 0 \right )$
$y$Intercept
$\left ( 0 , 4 \right )$
$x = 1$
$ $ Solve a solution to $ x$
$\color{#FF6800}{ 4 } \color{#FF6800}{ + } \color{#FF6800}{ x } = 5$
$ $ Organize the expression $ $
$\color{#FF6800}{ x } \color{#FF6800}{ + } \color{#FF6800}{ 4 } = 5$
$x \color{#FF6800}{ + } \color{#FF6800}{ 4 } = 5$
$ $ Move the constant to the right side and change the sign $ $
$x = 5 \color{#FF6800}{ - } \color{#FF6800}{ 4 }$
$x = \color{#FF6800}{ 5 } \color{#FF6800}{ - } \color{#FF6800}{ 4 }$
$ $ Subtract $ 4 $ from $ 5$
$x = \color{#FF6800}{ 1 }$
Solution search results
$2$ 2 $2\sqrt{32^{2}} +x-5\sqrt{3} $
7th-9th grade
Other
15 + x = 5x +3
1st-6th grade
Calculus
$\left(1\right)$ $17+x=5$
1st-6th grade
Algebra
![search-thumbnail-\sqrt[3]{12-x}+3\sqrt{14+x}=2](https://thumb-m.mathpresso.io/qanda-thumbnail-storage/questions/dPmF4aCBDtn5U5gFavirMCRWU9eCPaCwLcAVT6FMDfzYfKVCr6.jpg?target_format=webp&width=652)
$\sqrt [3] {12-x} +3\sqrt{14+x} =2$
10th-13th grade
Calculus
$20$ $-4+\dfrac {2} {3}x=-14$
10th-13th grade
Other
Have you found the solution you wanted?
Try againTry more features at Qanda!
Search by problem imageAsk 1:1 question to TOP class teachersAI recommend problems and video lecture