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Formula
Calculate the value
Answer
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$4 \sqrt{ 27 } \div 6 \sqrt{ 3 } \times 3 \sqrt{ 2 }$
$6 \sqrt{ 2 }$
Calculate the value
$\color{#FF6800}{ 4 } \sqrt{ \color{#FF6800}{ 27 } } \color{#FF6800}{ \div } \left ( \color{#FF6800}{ 6 } \sqrt{ \color{#FF6800}{ 3 } } \right ) \color{#FF6800}{ \times } \color{#FF6800}{ 3 } \sqrt{ \color{#FF6800}{ 2 } }$
$ $ Calculate the value that contains root $ $
$\color{#FF6800}{ 6 } \sqrt{ \color{#FF6800}{ 2 } }$
Solution search results
search-thumbnail-What is the inverse of $g\left(x\right)=\sqrt{x-1} $ $Og\left(x\right)=\sqrt{x+1} $ $+1$ $g^{'}\left(x\right)=5-$ $y_{9}$ $g\sqrt{ef\left(x\left(nght\right)} =\left(f_{tac\left(x+1\right)0sq\pi \left(x\right)}$ $Og^{'}\left(x\right)=x^{2}+1$ $○g\left(x\right)=x^{2}-1$ « Previous Ne
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search-thumbnail-What is the inverse of $g\left(x\right)=\sqrt{x-1} $ $Og\left(x\right)=\sqrt{x+1} $ $+1$ $g^{'}\left(x\right)=5-$ $y_{9}$ $g\sqrt{ef\left(x\left(nght\right)} =\left(f_{tac\left(x+1\right)0sq\pi \left(x\right)}$ $Og^{'}\left(x\right)=x^{2}+1$ $○g\left(x\right)=x^{2}-1$ « Previous Ne
Other
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search-thumbnail-The rationalizing factor of \sqrt{23} is $°$ $Options^{°}$ $0$ A 24 23 C \sqrt{23} D None of these
7th-9th grade
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