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Formula
Find the difference
Answer
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$4 \dfrac{ 5 }{ 6 } -2 \dfrac{ 3 }{ 10 }$
$\dfrac { 38 } { 15 }$
Find the difference
$\color{#FF6800}{ 4 \dfrac { 5 } { 6 } } - 2 \dfrac { 3 } { 10 }$
$ $ Convert mixed number into improper fraction $ $
$\color{#FF6800}{ \dfrac { 29 } { 6 } } - 2 \dfrac { 3 } { 10 }$
$\dfrac { 29 } { 6 } \color{#FF6800}{ - } \color{#FF6800}{ 2 \dfrac { 3 } { 10 } }$
$ $ Convert mixed number into improper fraction $ $
$\dfrac { 29 } { 6 } \color{#FF6800}{ - } \color{#FF6800}{ \dfrac { 23 } { 10 } }$
$\dfrac { 29 } { \color{#FF6800}{ 6 } } - \dfrac { 23 } { \color{#FF6800}{ 10 } }$
$ $ The smallest common multiple in denominator is $ 30$
$\dfrac { 29 } { \color{#FF6800}{ 6 } } - \dfrac { 23 } { \color{#FF6800}{ 10 } }$
$\dfrac { 29 } { 6 } - \dfrac { 23 } { 10 }$
$ $ Multiply the denominator and the numerator so that the denominator is the smallest common multiple $ $
$\dfrac { 29 \times \color{#FF6800}{ 5 } } { 6 \times \color{#FF6800}{ 5 } } - \dfrac { 23 \times \color{#FF6800}{ 3 } } { 10 \times \color{#FF6800}{ 3 } }$
$\color{#FF6800}{ \dfrac { 29 \times 5 } { 6 \times 5 } } \color{#FF6800}{ - } \color{#FF6800}{ \dfrac { 23 \times 3 } { 10 \times 3 } }$
$ $ Organize the expression $ $
$\color{#FF6800}{ \dfrac { 145 } { 30 } } \color{#FF6800}{ - } \color{#FF6800}{ \dfrac { 69 } { 30 } }$
$\color{#FF6800}{ \dfrac { 145 } { 30 } } \color{#FF6800}{ - } \color{#FF6800}{ \dfrac { 69 } { 30 } }$
$ $ Since the denominator is the same as $ 30 $ , combine the fractions into one $ $
$\color{#FF6800}{ \dfrac { 145 - 69 } { 30 } }$
$\dfrac { \color{#FF6800}{ 145 } \color{#FF6800}{ - } \color{#FF6800}{ 69 } } { 30 }$
$ $ Subtract $ 69 $ from $ 145$
$\dfrac { \color{#FF6800}{ 76 } } { 30 }$
$\color{#FF6800}{ \dfrac { 76 } { 30 } }$
$ $ Reduce the fraction to the lowest term $ $
$\color{#FF6800}{ \dfrac { 38 } { 15 } }$
Solution search results
search-thumbnail-
$1.$ $\dfrac {5} {7}-\dfrac {2} {7}$ $3.$ $\dfrac {3} {4}-\dfrac {2} {3}$ $5$ $\dfrac {9} {10}-\dfrac {3} {10}-\dfrac {2} {10}$ 
$2$ $\dfrac {9} {10}+\dfrac {3} {10}$ $4$ $\dfrac {5} {6}+\dfrac {1} {7}$ $6$ $\dfrac {2} {7}+\dfrac {3} {7}+\dfrac {5} {7}$
1st-6th grade
Other
search-thumbnail-$5\dfrac {3} {10}-1\dfrac {1} {10}=4\bar{i0} ^{-2^{4\dfrac {1} {5}}}$ $6$ $\dfrac {6} {12}-6\dfrac {2} {12}=$ 
$119$ $7\dfrac {8} {12}-3\dfrac {6} {12}=412\dfrac {2} {b}$ $6\dfrac {5} {6}.4\dfrac {1} {6}=$ 
$2\dfrac {8} {9}-1\dfrac {2} {9}=1\dfrac {6} {9}$ $8\dfrac {4} {6}-8\dfrac {1} {6}=$ 
$3\dfrac {5} {6}-2\dfrac {1} {6}=$ $8\dfrac {9} {10}-8\dfrac {1} {10}=$ 13 
$8$ 
$5\dfrac {7} {10}-5\dfrac {5} {10}=1$ $6\dfrac {7} {10}.3\dfrac {5} {10}=$
10th-13th grade
Other
search-thumbnail-Which of the following rational numbers are 
equivalent? 
$0Ptionsy$ 
A \frac{5}{6}, \frac{30}{36} 
B $s\sqrt{rac\left(} -2\right)\left(3\right)\sqrt{1rac} \sqrt{4\right)16\right)4} $ 
C $s\sqrt{11aC\left(} -4\right)1-7b,\sqrt{1rac\left(16\sqrt{35\right)9} } $ 
D \frac{1}{2},\frac{3}{8}
7th-9th grade
Other
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