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Answer
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$4 \dfrac{ 1 }{ 2 } \div 5 \dfrac{ 1 }{ 4 } - \dfrac{ 4 }{ 9 }$
$\dfrac { 26 } { 63 }$
Calculate the value
$\color{#FF6800}{ 4 \dfrac { 1 } { 2 } } \div 5 \dfrac { 1 } { 4 } - \dfrac { 4 } { 9 }$
$ $ Convert mixed number into improper fraction $ $
$\color{#FF6800}{ \dfrac { 9 } { 2 } } \div 5 \dfrac { 1 } { 4 } - \dfrac { 4 } { 9 }$
$\dfrac { 9 } { 2 } \div \color{#FF6800}{ 5 \dfrac { 1 } { 4 } } - \dfrac { 4 } { 9 }$
$ $ Convert mixed number into improper fraction $ $
$\dfrac { 9 } { 2 } \div \color{#FF6800}{ \dfrac { 21 } { 4 } } - \dfrac { 4 } { 9 }$
$\color{#FF6800}{ \dfrac { 9 } { 2 } } \color{#FF6800}{ \div } \color{#FF6800}{ \dfrac { 21 } { 4 } } - \dfrac { 4 } { 9 }$
$ $ Calculate division of fractions $ $
$\color{#FF6800}{ \dfrac { 6 } { 7 } } - \dfrac { 4 } { 9 }$
$\color{#FF6800}{ \dfrac { 6 } { 7 } } \color{#FF6800}{ - } \color{#FF6800}{ \dfrac { 4 } { 9 } }$
$ $ Find the difference between the two fractions $ \dfrac { 6 } { 7 } $ and $ - \dfrac { 4 } { 9 }$
$\color{#FF6800}{ \dfrac { 26 } { 63 } }$
Solution search results
search-thumbnail-$1.\dfrac {2} {3}\times \dfrac {1} {2}$ $2.\dfrac {3} {4}\times \dfrac {1} {9}$ $3.3\times \dfrac {4} {9}$ 
$4.\dfrac {1} {5}\times \dfrac {1} {4}$ $5.\dfrac {1} {4}\times \dfrac {4} {5}$ $6.\dfrac {4} {9}\times \dfrac {3} {4}$ 
7. $\dfrac {13} {21}\times \dfrac {7} {13}$ 8. $\dfrac {7} {8}\times \dfrac {4} {9}$ 9. $\dfrac {5} {7}\times \dfrac {7} {10}$ 
10. $\dfrac {4} {5}\times \dfrac {5} {14}$ 11. $\dfrac {1} {4}\times \dfrac {5} {8}$ $12.\dfrac {2} {3}\times \dfrac {5} {9}$ 
13. $\dfrac {4} {5}\times 7$ 14. $2\dfrac {2} {5}\times 1\dfrac {3} {7}$ $15.6\times \dfrac {2} {3}$ 
$16.3\dfrac {3} {4}\times 12$ 17. $1\dfrac {5} {9}\times 2\dfrac {4} {7}$ $18.4\dfrac {1} {3}\times \dfrac {1} {2}$
10th-13th grade
Algebra
search-thumbnail-$2.$ 2. State whether the statements are true or false. 
$a\right)$ $\dfrac {2} {3}$ $-\dfrac {1} {2}=\dfrac {1} {2}-\dfrac {1} {3}$ b) $\dfrac {3} {2}-\left(\dfrac {1} {4}-\dfrac {6} {8}\right)=\left(\dfrac {3} {2}-\dfrac {1} {4}\right)$ $-\dfrac {6} {8}$ 
c) $\dfrac {-5} {9}-0=\dfrac {-5} {9}$ $\right)$ $\dfrac {5} {6}-\left(\dfrac {-5} {6}\right)=0$ 
e) $\right)$ $\dfrac {3} {4}-\dfrac {1} {2}=\dfrac {1} {4}$ $\right)$ $0-\dfrac {4} {9}=\dfrac {4} {9}$
7th-9th grade
Calculus
search-thumbnail-$2.$ 2. State whether the statements are true or false. 
$a\right)$ $\dfrac {2} {3}-\dfrac {1} {2}=\dfrac {1} {2}-\dfrac {1} {3}$ b) $\dfrac {3} {2}-\left(\dfrac {1} {4}-\dfrac {6} {8}\right)=\left(\dfrac {3} {2}-\dfrac {1} {4}\right)-$ $-\dfrac {6} {8}$ 
c) $\dfrac {-5} {9}-0=$ $-0=\dfrac {-5} {9}$ d) $\dfrac {5} {6}-\left(\dfrac {-5} {6}\right)=0$ 
$e\right)$ $\dfrac {3} {4}-\dfrac {1} {2}=\dfrac {1} {4}$ $0-\dfrac {4} {9}=\dfrac {4} {9}$ 
$5$ $4$ $7$
7th-9th grade
Calculus
search-thumbnail-$=$ 
$e\right)$ $\dfrac {3} {4}-$ $-\dfrac {1} {2}=\dfrac {1} {4}$ $\right)$ $\right)$ $0--$ $9$ $\bar{\dfrac {4} {9}=\dfrac {4} {9}} $ 
$3$ Subtract the sum of $\dfrac {5} {9}$ and $\dfrac {4} {9}$ from the sum of $\dfrac {7} {11}$ and $\dfrac {3} {9}$
1st-6th grade
Other
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