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Formula
Calculate the value
Answer
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$32+ \dfrac{ 45 }{ 3 } - \left( 17+3 \times 4 \right) +2 \times 2 \times 2-8$
$18$
Calculate the value
$32 + \color{#FF6800}{ \dfrac { 45 } { 3 } } - \left ( 17 + 3 \times 4 \right ) + 2 \times 2 \times 2 - 8$
$ $ Reduce the fraction $ $
$32 + \color{#FF6800}{ 15 } - \left ( 17 + 3 \times 4 \right ) + 2 \times 2 \times 2 - 8$
$32 + 15 - \left ( 17 + \color{#FF6800}{ 3 } \color{#FF6800}{ \times } \color{#FF6800}{ 4 } \right ) + 2 \times 2 \times 2 - 8$
$ $ Multiply $ 3 $ and $ 4$
$32 + 15 - \left ( 17 + \color{#FF6800}{ 12 } \right ) + 2 \times 2 \times 2 - 8$
$32 + 15 - \left ( \color{#FF6800}{ 17 } \color{#FF6800}{ + } \color{#FF6800}{ 12 } \right ) + 2 \times 2 \times 2 - 8$
$ $ Add $ 17 $ and $ 12$
$32 + 15 - \color{#FF6800}{ 29 } + 2 \times 2 \times 2 - 8$
$32 + 15 - 29 + \color{#FF6800}{ 2 } \color{#FF6800}{ \times } \color{#FF6800}{ 2 } \color{#FF6800}{ \times } \color{#FF6800}{ 2 } - 8$
$ $ Multiply the numbers $ $
$32 + 15 - 29 + \color{#FF6800}{ 8 } - 8$
$32 + 15 - 29 \color{#FF6800}{ + } \color{#FF6800}{ 8 } \color{#FF6800}{ - } \color{#FF6800}{ 8 }$
$ $ Remove the two numbers if the values are the same and the signs are different $ $
$32 + 15 - 29$
$\color{#FF6800}{ 32 } \color{#FF6800}{ + } \color{#FF6800}{ 15 } \color{#FF6800}{ - } \color{#FF6800}{ 29 }$
$ $ Calculate the sum or the difference $ $
$\color{#FF6800}{ 18 }$
Solution search results
search-thumbnail-If the sum of two consecutive 
numbers is $45$ and one number is $X$ 
.This statement in the form of 
equation $1s:$ 
$\left(1$ Point) $\right)$ 
$○5x+1$ $1eft\left(x+1$ $r1gnt\right)=45s$ 
$○sx+1ef\left(x+2$ $r1gnt\right)=145s$ 
$sx+1x=45s$
7th-9th grade
Algebra
search-thumbnail-$s|ef\left(-1n$ $\left($ }\right)^{50}\ $\right)$ \ | | is\ equal\ to\ $S$ 
$s1S$ 
$S-1S$ 
$s2S$ 
$s50s$
7th-9th grade
Other
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