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Solve the equation
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$y = 3 - 1$
$y = x \times \dfrac { 1 } { 4 } + \dfrac { 1 } { 4 }$
$x$-intercept
$\left ( - 1 , 0 \right )$
$y$-intercept
$\left ( 0 , \dfrac { 1 } { 4 } \right )$
$3-1 = x \times \dfrac{ 1 }{ 4 } + \dfrac{ 1 }{ 4 }$
$x = 7$
 Solve a solution to $x$
$\color{#FF6800}{ 3 } \color{#FF6800}{ - } \color{#FF6800}{ 1 } = x \times \dfrac { 1 } { 4 } + \dfrac { 1 } { 4 }$
 Subtract $1$ from $3$
$\color{#FF6800}{ 2 } = x \times \dfrac { 1 } { 4 } + \dfrac { 1 } { 4 }$
$2 = \color{#FF6800}{ x } \color{#FF6800}{ \times } \color{#FF6800}{ \dfrac { 1 } { 4 } } + \dfrac { 1 } { 4 }$
 Simplify the expression 
$2 = \color{#FF6800}{ \dfrac { 1 } { 4 } } \color{#FF6800}{ x } + \dfrac { 1 } { 4 }$
$2 = \color{#FF6800}{ \dfrac { 1 } { 4 } } \color{#FF6800}{ x } + \dfrac { 1 } { 4 }$
 Calculate the multiplication expression 
$2 = \color{#FF6800}{ \dfrac { x } { 4 } } + \dfrac { 1 } { 4 }$
$\color{#FF6800}{ 2 } = \color{#FF6800}{ \dfrac { x } { 4 } } \color{#FF6800}{ + } \color{#FF6800}{ \dfrac { 1 } { 4 } }$
 Multiply both sides by the least common multiple for the denominators to eliminate the fraction 
$\color{#FF6800}{ 8 } = \color{#FF6800}{ x } \color{#FF6800}{ + } \color{#FF6800}{ 1 }$
$8 = \color{#FF6800}{ x } + 1$
 Move the variable to the left-hand side and change the symbol 
$8 \color{#FF6800}{ - } \color{#FF6800}{ x } = 1$
$\color{#FF6800}{ 8 } - x = 1$
 Move the constant to the right side and change the sign 
$- x = 1 \color{#FF6800}{ - } \color{#FF6800}{ 8 }$
$- x = \color{#FF6800}{ 1 } \color{#FF6800}{ - } \color{#FF6800}{ 8 }$
 Subtract $8$ from $1$
$- x = \color{#FF6800}{ - } \color{#FF6800}{ 7 }$
$\color{#FF6800}{ - } \color{#FF6800}{ x } = \color{#FF6800}{ - } \color{#FF6800}{ 7 }$
 Change the sign of both sides of the equation 
$\color{#FF6800}{ x } = \color{#FF6800}{ - } \left ( \color{#FF6800}{ - } \color{#FF6800}{ 7 } \right )$
$x = \color{#FF6800}{ - } \left ( \color{#FF6800}{ - } 7 \right )$
 Simplify Minus 
$x = 7$
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