Calculator search results

Formula
Solve the equation
Answer
circle-check-icon
expand-arrow-icon
expand-arrow-icon
expand-arrow-icon
Graph
$y = 3 - 1$
$y = x \times \dfrac { 1 } { 4 } + \dfrac { 1 } { 4 }$
$x$-intercept
$\left ( - 1 , 0 \right )$
$y$-intercept
$\left ( 0 , \dfrac { 1 } { 4 } \right )$
$3-1 = x \times \dfrac{ 1 }{ 4 } + \dfrac{ 1 }{ 4 }$
$x = 7$
$ $ Solve a solution to $ x$
$\color{#FF6800}{ 3 } \color{#FF6800}{ - } \color{#FF6800}{ 1 } = x \times \dfrac { 1 } { 4 } + \dfrac { 1 } { 4 }$
$ $ Subtract $ 1 $ from $ 3$
$\color{#FF6800}{ 2 } = x \times \dfrac { 1 } { 4 } + \dfrac { 1 } { 4 }$
$2 = \color{#FF6800}{ x } \color{#FF6800}{ \times } \color{#FF6800}{ \dfrac { 1 } { 4 } } + \dfrac { 1 } { 4 }$
$ $ Simplify the expression $ $
$2 = \color{#FF6800}{ \dfrac { 1 } { 4 } } \color{#FF6800}{ x } + \dfrac { 1 } { 4 }$
$2 = \color{#FF6800}{ \dfrac { 1 } { 4 } } \color{#FF6800}{ x } + \dfrac { 1 } { 4 }$
$ $ Calculate the multiplication expression $ $
$2 = \color{#FF6800}{ \dfrac { x } { 4 } } + \dfrac { 1 } { 4 }$
$\color{#FF6800}{ 2 } = \color{#FF6800}{ \dfrac { x } { 4 } } \color{#FF6800}{ + } \color{#FF6800}{ \dfrac { 1 } { 4 } }$
$ $ Multiply both sides by the least common multiple for the denominators to eliminate the fraction $ $
$\color{#FF6800}{ 8 } = \color{#FF6800}{ x } \color{#FF6800}{ + } \color{#FF6800}{ 1 }$
$8 = \color{#FF6800}{ x } + 1$
$ $ Move the variable to the left-hand side and change the symbol $ $
$8 \color{#FF6800}{ - } \color{#FF6800}{ x } = 1$
$\color{#FF6800}{ 8 } - x = 1$
$ $ Move the constant to the right side and change the sign $ $
$- x = 1 \color{#FF6800}{ - } \color{#FF6800}{ 8 }$
$- x = \color{#FF6800}{ 1 } \color{#FF6800}{ - } \color{#FF6800}{ 8 }$
$ $ Subtract $ 8 $ from $ 1$
$- x = \color{#FF6800}{ - } \color{#FF6800}{ 7 }$
$\color{#FF6800}{ - } \color{#FF6800}{ x } = \color{#FF6800}{ - } \color{#FF6800}{ 7 }$
$ $ Change the sign of both sides of the equation $ $
$\color{#FF6800}{ x } = \color{#FF6800}{ - } \left ( \color{#FF6800}{ - } \color{#FF6800}{ 7 } \right )$
$x = \color{#FF6800}{ - } \left ( \color{#FF6800}{ - } 7 \right )$
$ $ Simplify Minus $ $
$x = 7$
$ $ 그래프 보기 $ $
Graph
Solution search results
search-thumbnail-Question $4$ 
If $x$ is $6$ what $|s$ 
$\dfrac {1} {3}x$ 
$1frac\left(1\right)\left(3\right)x$
1st-6th grade
Other
search-thumbnail-$\left($ (d) $\right)$ $7\dfrac {3} {4}+ \begin{cases} - \\ 2\dfrac {1} {6}-\left(\dfrac {2} {3}\times \dfrac {3} {4}-\dfrac {1} {5}\right)\right) \end{cases} $ $3$ $-1-$ 
$8$
7th-9th grade
Calculus
search-thumbnail-$11.$ Question $11$ 
Solve the $:$ $folloMlng'$ $0<θ<90^{°}$ 
$\left(1\right)$ $2sin^{2}θ=1\right)$ $\left(rac\left(3\right)\left(2\right)\right)$ 
$\left(11\right)$ $3tan^{2}θ+2=3$ 
$\left(111\right)cos^{2}θ$ $11rac\left(1\right)\left(4\right)\right)=$ 
$c\left(1\right)\left(4\right)\right)=11113c\left(1\right)\left(2\right)\right)$
10th-13th grade
Trigonometry
search-thumbnail-Which of the following rational numbers are 
equivalent? 
$0Ptionsy$ 
A \frac{5}{6}, \frac{30}{36} 
B $s\sqrt{rac\left(} -2\right)\left(3\right)\sqrt{1rac} \sqrt{4\right)16\right)4} $ 
C $s\sqrt{11aC\left(} -4\right)1-7b,\sqrt{1rac\left(16\sqrt{35\right)9} } $ 
D \frac{1}{2},\frac{3}{8}
7th-9th grade
Other
Have you found the solution you wanted?
Try again
Try more features at QANDA!
Search by problem image
Ask 1:1 question to TOP class teachers
AI recommend problems and video lecture
apple logogoogle play logo