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Formula
Find the approximate value
Answer
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Square root
Answer
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$3 \times \sqrt{ 7 }$
$\approx 7.9373$
Find the approximate value
$\color{#FF6800}{ 3 } \sqrt{ \color{#FF6800}{ 7 } }$
$ $ Find the approximate value of the square root $ $
$\approx \color{#FF6800}{ 7.9373 }$
$\sqrt{ 63 }$
Change the expression
$\color{#FF6800}{ 3 } \sqrt{ \color{#FF6800}{ 7 } }$
$ $ Put the coefficient into the square root $ $
$\sqrt{ \color{#FF6800}{ 3 } ^ { \color{#FF6800}{ 2 } } \color{#FF6800}{ \times } \color{#FF6800}{ 7 } }$
$\sqrt{ \color{#FF6800}{ 3 } ^ { \color{#FF6800}{ 2 } } \color{#FF6800}{ \times } \color{#FF6800}{ 7 } }$
$ $ Simplify the expression $ $
$\sqrt{ \color{#FF6800}{ 9 } \color{#FF6800}{ \times } \color{#FF6800}{ 7 } }$
$\sqrt{ \color{#FF6800}{ 9 } \color{#FF6800}{ \times } \color{#FF6800}{ 7 } }$
$ $ Multiply $ 9 $ and $ 7$
$\sqrt{ \color{#FF6800}{ 63 } }$
Solution search results
search-thumbnail-$Nln8+$ $1s$ $\left(\right)e$ Geometrie Mean $\left(Neox$ s OF 
$\right)$ $-$ $-\dfrac {1} {n}$ $-$ $1-1y$ $-2$ $3^{-4}$ 
$\bar{7} $ $1^{7}1^{3},\sqrt{7} $ $\right)^{4a}$ 
$2\right)$ $\sqrt{7} $ $1^{7}1^{3},\sqrt{7} $ 
$3\longdiv{4,8,1y}$
10th-13th grade
Geometry
search-thumbnail-$4$ Find the missing lengths. 
$b$ 
$45^{°}$ 
$2\sqrt{2} $ 
$F$ $a=2$ and $b=2+sq\pi \left(2\right)$ 
$6$ $a=sq\pi \left(2\right)$ and $b=2\times sq\pi \left(2\right)$ 
$I$ 
$H$ $a$ $=2\times sq\pi \left(2\right)$ and $b=2\times sq\pi \left(2\right)$ 
$3$ a $=4$ and $b=2+sq\pi \left(2\right)$
10th-13th grade
Other
search-thumbnail-$x$ 
$45^{°}$ 
$6$ 
Find $x$ 
$O6$ 
$\square 6sq\pi \left(2\right)$ 
sqrt $\left(2\right)$ 
$○12sq$ 
$○3s$ sqrt $\left(2\right)$
10th-13th grade
Calculus
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