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Formula
Calculate the value
Answer
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$3 \sqrt{ 2 } + \sqrt{ 5 } -2 \sqrt{ 5 }$
$3 \sqrt{ 2 } - \sqrt{ 5 }$
Calculate the value
$3 \sqrt{ 2 } + \sqrt{ \color{#FF6800}{ 5 } } \color{#FF6800}{ - } \color{#FF6800}{ 2 } \sqrt{ \color{#FF6800}{ 5 } }$
$ $ Calculate between similar terms $ $
$3 \sqrt{ 2 } \color{#FF6800}{ - } \color{#FF6800}{ 1 } \sqrt{ \color{#FF6800}{ 5 } }$
$3 \sqrt{ 2 } \color{#FF6800}{ - } \color{#FF6800}{ 1 } \sqrt{ 5 }$
$ $ Multiplying any number by 1 does not change the value $ $
$3 \sqrt{ 2 } - \sqrt{ 5 }$
Solution search results
search-thumbnail-AREAS 
$4$ The area bounded by $y^{2}=4x$ with the lines 
$x=2$ and $x=5$ is 
$\dfrac {8} {3}\left(5\sqrt{5} -2\sqrt{2} \right)$ $2\right)$ $\dfrac {4} {3}\left(5\sqrt{5} -2\sqrt{2} \right)$ 
$1\right)$ $\dfrac {8} {3}\left(5\sqrt{5} $ 
$3\right)$ $5\sqrt{5} -2\sqrt{2} $ $4\right)$ $\dfrac {16} {3}$
10th-13th grade
Calculus
search-thumbnail-Retiep 
$°$ $\right)$ $8\sqrt{6} -\sqrt{5} $ $3\sqrt{5} -2\sqrt{6} $
10th-13th grade
Other
search-thumbnail-The rationalizing factor of \sqrt{23} is 
$°$ $Options^{°}$ $0$ 
A 24 
23 
C \sqrt{23} 
D None of these
7th-9th grade
Other
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