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Solve the equation
Answer
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Graph
$y = 3 \left ( x + 5 \right )$
$y = 7 x - 9$
$x$Intercept
$\left ( - 5 , 0 \right )$
$y$Intercept
$\left ( 0 , 15 \right )$
$x$Intercept
$\left ( \dfrac { 9 } { 7 } , 0 \right )$
$y$Intercept
$\left ( 0 , - 9 \right )$
$3 \left( x+5 \right) = 7x-9$
$x = 6$
$ $ Solve a solution to $ x$
$\color{#FF6800}{ 3 } \left ( \color{#FF6800}{ x } \color{#FF6800}{ + } \color{#FF6800}{ 5 } \right ) = 7 x - 9$
$ $ Multiply each term in parentheses by $ 3$
$\color{#FF6800}{ 3 } \color{#FF6800}{ x } \color{#FF6800}{ + } \color{#FF6800}{ 3 } \color{#FF6800}{ \times } \color{#FF6800}{ 5 } = 7 x - 9$
$3 x + \color{#FF6800}{ 3 } \color{#FF6800}{ \times } \color{#FF6800}{ 5 } = 7 x - 9$
$ $ Multiply $ 3 $ and $ 5$
$3 x + \color{#FF6800}{ 15 } = 7 x - 9$
$3 x + 15 = \color{#FF6800}{ 7 } \color{#FF6800}{ x } - 9$
$ $ Move the variable to the left-hand side and change the symbol $ $
$3 x + 15 \color{#FF6800}{ - } \color{#FF6800}{ 7 } \color{#FF6800}{ x } = - 9$
$3 x \color{#FF6800}{ + } \color{#FF6800}{ 15 } - 7 x = - 9$
$ $ Move the constant to the right side and change the sign $ $
$3 x - 7 x = - 9 \color{#FF6800}{ - } \color{#FF6800}{ 15 }$
$\color{#FF6800}{ 3 } \color{#FF6800}{ x } \color{#FF6800}{ - } \color{#FF6800}{ 7 } \color{#FF6800}{ x } = - 9 - 15$
$ $ Organize the expression $ $
$\color{#FF6800}{ - } \color{#FF6800}{ 4 } \color{#FF6800}{ x } = - 9 - 15$
$- 4 x = \color{#FF6800}{ - } \color{#FF6800}{ 9 } \color{#FF6800}{ - } \color{#FF6800}{ 15 }$
$ $ Find the sum of the negative numbers $ $
$- 4 x = \color{#FF6800}{ - } \color{#FF6800}{ 24 }$
$\color{#FF6800}{ - } \color{#FF6800}{ 4 } \color{#FF6800}{ x } = \color{#FF6800}{ - } \color{#FF6800}{ 24 }$
$ $ Change the sign of both sides of the equation $ $
$4 x = 24$
$\color{#FF6800}{ 4 } \color{#FF6800}{ x } = \color{#FF6800}{ 24 }$
$ $ Divide both sides by the same number $ $
$\color{#FF6800}{ x } = \color{#FF6800}{ 6 }$
$ $ 그래프 보기 $ $
Graph
Solution search results
search-thumbnail-If the sum of two consecutive 
numbers is $45$ and one number is $X$ 
.This statement in the form of 
equation $1s:$ 
$\left(1$ Point) $\right)$ 
$○5x+1$ $1eft\left(x+1$ $r1gnt\right)=45s$ 
$○sx+1ef\left(x+2$ $r1gnt\right)=145s$ 
$sx+1x=45s$
7th-9th grade
Algebra
search-thumbnail-$s|ef\left(-1n$ $\left($ }\right)^{50}\ $\right)$ \ | | is\ equal\ to\ $S$ 
$s1S$ 
$S-1S$ 
$s2S$ 
$s50s$
7th-9th grade
Other
search-thumbnail-Given the set of ordered pairs $\left(\left(-7.0\right),\left(-6,5\right),\left(-5,-3\right),\left(-1,2\right)$ $\left(1,6\right),\left(2,-2\right)$ $\left(5,3\right)\left(7,-8\right)\right)$ 
Find f(7)fAleft(7\right) 
O a 
O b -8 
6. 
$5$
7th-9th grade
Algebra
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