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Formula
Find the difference
Answer
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$3 \dfrac{ 5 }{ 6 } -1 \dfrac{ 5 }{ 14 }$
$\dfrac { 52 } { 21 }$
Find the difference
$\color{#FF6800}{ 3 \dfrac { 5 } { 6 } } - 1 \dfrac { 5 } { 14 }$
$ $ Convert mixed number into improper fraction $ $
$\color{#FF6800}{ \dfrac { 23 } { 6 } } - 1 \dfrac { 5 } { 14 }$
$\dfrac { 23 } { 6 } \color{#FF6800}{ - } \color{#FF6800}{ 1 \dfrac { 5 } { 14 } }$
$ $ Convert mixed number into improper fraction $ $
$\dfrac { 23 } { 6 } \color{#FF6800}{ - } \color{#FF6800}{ \dfrac { 19 } { 14 } }$
$\dfrac { 23 } { \color{#FF6800}{ 6 } } - \dfrac { 19 } { \color{#FF6800}{ 14 } }$
$ $ The smallest common multiple in denominator is $ 42$
$\dfrac { 23 } { \color{#FF6800}{ 6 } } - \dfrac { 19 } { \color{#FF6800}{ 14 } }$
$\dfrac { 23 } { 6 } - \dfrac { 19 } { 14 }$
$ $ Multiply the denominator and the numerator so that the denominator is the smallest common multiple $ $
$\dfrac { 23 \times \color{#FF6800}{ 7 } } { 6 \times \color{#FF6800}{ 7 } } - \dfrac { 19 \times \color{#FF6800}{ 3 } } { 14 \times \color{#FF6800}{ 3 } }$
$\color{#FF6800}{ \dfrac { 23 \times 7 } { 6 \times 7 } } \color{#FF6800}{ - } \color{#FF6800}{ \dfrac { 19 \times 3 } { 14 \times 3 } }$
$ $ Organize the expression $ $
$\color{#FF6800}{ \dfrac { 161 } { 42 } } \color{#FF6800}{ - } \color{#FF6800}{ \dfrac { 57 } { 42 } }$
$\color{#FF6800}{ \dfrac { 161 } { 42 } } \color{#FF6800}{ - } \color{#FF6800}{ \dfrac { 57 } { 42 } }$
$ $ Since the denominator is the same as $ 42 $ , combine the fractions into one $ $
$\color{#FF6800}{ \dfrac { 161 - 57 } { 42 } }$
$\dfrac { \color{#FF6800}{ 161 } \color{#FF6800}{ - } \color{#FF6800}{ 57 } } { 42 }$
$ $ Subtract $ 57 $ from $ 161$
$\dfrac { \color{#FF6800}{ 104 } } { 42 }$
$\color{#FF6800}{ \dfrac { 104 } { 42 } }$
$ $ Reduce the fraction to the lowest term $ $
$\color{#FF6800}{ \dfrac { 52 } { 21 } }$
Solution search results
search-thumbnail-$a\right)05$ $-13$ 
$\dfrac {11} {12}$ d) $\right)\dfrac {3} {4}-\dfrac {1} {6}-\dfrac {5} {8}$ 
$1\dfrac {8} {9}$ noiea5 
h) $\right)$ $4\dfrac {5} {6}-2\dfrac {2} {7}-1\dfrac {3} {14}$ 
$3$ $1$
7th-9th grade
Other
search-thumbnail-Which of the following rational numbers are 
equivalent? 
$0Ptionsy$ 
A \frac{5}{6}, \frac{30}{36} 
B $s\sqrt{rac\left(} -2\right)\left(3\right)\sqrt{1rac} \sqrt{4\right)16\right)4} $ 
C $s\sqrt{11aC\left(} -4\right)1-7b,\sqrt{1rac\left(16\sqrt{35\right)9} } $ 
D \frac{1}{2},\frac{3}{8}
7th-9th grade
Other
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