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Solve the equation
Answer
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Graph
$x = 2 y$
$x = - 1$
$x$Intercept
$\left ( 0 , 0 \right )$
$y$Intercept
$\left ( 0 , 0 \right )$
$y = - \dfrac { 1 } { 2 }$
$ $ Solve a solution to $ y$
$\color{#FF6800}{ 2 } \color{#FF6800}{ y } = \color{#FF6800}{ - } \color{#FF6800}{ 1 }$
$ $ Divide both sides by the same number $ $
$\color{#FF6800}{ y } = \color{#FF6800}{ - } \color{#FF6800}{ \dfrac { \color{#FF6800}{ 1 } } { \color{#FF6800}{ 2 } } }$
Solution search results
search-thumbnail-(-x T -2y
$\left(-x$ T $-2y$ $=-16\right)$ $\left(-4x$ $-4y$ $=-24\right)$ $try$ $16$ $\int _{x+\sqrt{} } ^{-4}^{y}$ $=-24$ $0$
7th-9th grade
Algebra
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search-thumbnail-\dfrac{x}{\dfrac{\dfrac{\dfrac{-1}{0}}{1}}{2}} y 5
$④$ $y=$ $2x+2$ $\dfrac {x} {\dfrac {\dfrac {\dfrac {-1} {0}} {1}} {2}}$ $y$ $5$
10th-13th grade
Algebra
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search-thumbnail-1. 3x-2y=-16
$1.$ $3x-2y=-16$
10th-13th grade
Other
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search-thumbnail-y^{2} -5x+12y=-16
$y^{2}$ $-5x+12y=-16$
10th-13th grade
Calculus
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search-thumbnail-x+2y=-1
$x+2y=-1$ $2x-3y=12$
Other
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search-thumbnail-\dfrac{\square}{\square} -y-z=-3
$1.$ $7l-2y=-1$ $\dfrac {\square } {\square }$ $-y-z=-3$ $y-z=2$ $\square $ $-$
10th-13th grade
Other
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