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Formula
Solve the equation
Answer
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$y = 2 x + 5$
$y = 9$
$x$-intercept
$\left ( - \dfrac { 5 } { 2 } , 0 \right )$
$y$-intercept
$\left ( 0 , 5 \right )$
$2x+5 = 9$
$x = 2$
$ $ Solve a solution to $ x$
$2 x \color{#FF6800}{ + } \color{#FF6800}{ 5 } = 9$
$ $ Move the constant to the right side and change the sign $ $
$2 x = 9 \color{#FF6800}{ - } \color{#FF6800}{ 5 }$
$2 x = \color{#FF6800}{ 9 } \color{#FF6800}{ - } \color{#FF6800}{ 5 }$
$ $ Subtract $ 5 $ from $ 9$
$2 x = \color{#FF6800}{ 4 }$
$\color{#FF6800}{ 2 } \color{#FF6800}{ x } = \color{#FF6800}{ 4 }$
$ $ Divide both sides by the same number $ $
$\color{#FF6800}{ x } = \color{#FF6800}{ 2 }$
$ $ 그래프 보기 $ $
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Solution search results
search-thumbnail-$3x+2y=9$ $2x+5y=17$
10th-13th grade
Algebra
Check solution
search-thumbnail-$4$ Seven times the sum of $5$ $5i\times $ times $5$ a number $y$ less than four is equal to eight. B. $D1RECT1ONS$ Translate each mathematical sentence into verbal sentence. $1$ $2x+5=9$ $2.9+3x=18$ $3.2x-16\leq 4$ $4.2\left(x+1\right)=8$ $5.4m-3\geq 16$ Dy mass? nlute and sOlvent in % ti A0%
7th-9th grade
Algebra
Check solution
search-thumbnail-$3x+2y=9$ $2x+5y=17$
Other
Check solution
search-thumbnail-$3-\sqrt{2} \times +5=0$ $s0^{1}=$ $3-\sqrt{2} x+5=$ $0$ $\sqrt{} 2x+5$ = $3+0$ $\sqrt{2x} $ $\dfrac {2} {5}$ $\sqrt{8} $ $2x+5$ $=9$ $2x+5-9$ $axc=$ $2x-$ $9$ $=$ $-18$
1st-6th grade
Other
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search-thumbnail-$ACTm\pi TY$ $2°$ If the given mathematical sentence is a linear equation in one variable, write $LEOV$ If not, state the reason. $1$ $3x+5=9$ $2$ $x-4=11$ $3$ $2x^{2}+3=21$ $4$ $2x+3y=-4$ $5$ $5-x=10$
7th-9th grade
Other
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search-thumbnail-$x+y+$ $3=9$ $2x+sy+13=s2$ $2x+y-3=0$
10th-13th grade
Other
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