Calculator search results

Formula
Factorize the expression
Answer
circle-check-icon
expand-arrow-icon
expand-arrow-icon
expand-arrow-icon
$2x ^{ 3 } -7x ^{ 2 } +2x+3$
$\left ( x - 3 \right ) \left ( x - 1 \right ) \left ( 2 x + 1 \right )$
Arrange the expression in the form of factorization..
$\color{#FF6800}{ 2 } \color{#FF6800}{ x } ^ { \color{#FF6800}{ 3 } } \color{#FF6800}{ - } \color{#FF6800}{ 7 } \color{#FF6800}{ x } ^ { \color{#FF6800}{ 2 } } \color{#FF6800}{ + } \color{#FF6800}{ 2 } \color{#FF6800}{ x } \color{#FF6800}{ + } \color{#FF6800}{ 3 }$
$ $ Do factorization $ $
$\left ( \color{#FF6800}{ x } \color{#FF6800}{ - } \color{#FF6800}{ 1 } \right ) \left ( \color{#FF6800}{ 2 } \color{#FF6800}{ x } ^ { \color{#FF6800}{ 2 } } \color{#FF6800}{ - } \color{#FF6800}{ 5 } \color{#FF6800}{ x } \color{#FF6800}{ - } \color{#FF6800}{ 3 } \right )$
$\left ( x - 1 \right ) \left ( \color{#FF6800}{ 2 } \color{#FF6800}{ x } ^ { \color{#FF6800}{ 2 } } \color{#FF6800}{ - } \color{#FF6800}{ 5 } \color{#FF6800}{ x } \color{#FF6800}{ - } \color{#FF6800}{ 3 } \right )$
$ $ Use the factoring formula, $ acx^{2} + \left(ad + bc\right)x + bd = \left(ax+b\right)\left(cx+d\right)$
$\left ( x - 1 \right ) \left ( \color{#FF6800}{ 2 } \color{#FF6800}{ x } \color{#FF6800}{ + } \color{#FF6800}{ 1 } \right ) \left ( \color{#FF6800}{ 1 } \color{#FF6800}{ x } \color{#FF6800}{ - } \color{#FF6800}{ 3 } \right )$
$\left ( x - 1 \right ) \left ( 2 x + 1 \right ) \left ( \color{#FF6800}{ 1 } \color{#FF6800}{ x } \color{#FF6800}{ - } \color{#FF6800}{ 3 } \right )$
$ $ Expand the expression $ $
$\left ( x - 1 \right ) \left ( 2 x + 1 \right ) \left ( \color{#FF6800}{ x } \color{#FF6800}{ - } \color{#FF6800}{ 3 } \right )$
$\left ( x - 1 \right ) \left ( \color{#FF6800}{ 2 } \color{#FF6800}{ x } \color{#FF6800}{ + } \color{#FF6800}{ 1 } \right ) \left ( \color{#FF6800}{ x } \color{#FF6800}{ - } \color{#FF6800}{ 3 } \right )$
$ $ Sort the factors $ $
$\left ( x - 1 \right ) \left ( \color{#FF6800}{ x } \color{#FF6800}{ - } \color{#FF6800}{ 3 } \right ) \left ( \color{#FF6800}{ 2 } \color{#FF6800}{ x } \color{#FF6800}{ + } \color{#FF6800}{ 1 } \right )$
$\left ( \color{#FF6800}{ x } \color{#FF6800}{ - } \color{#FF6800}{ 1 } \right ) \left ( \color{#FF6800}{ x } \color{#FF6800}{ - } \color{#FF6800}{ 3 } \right ) \left ( \color{#FF6800}{ 2 } \color{#FF6800}{ x } \color{#FF6800}{ + } \color{#FF6800}{ 1 } \right )$
$ $ Sort the factors $ $
$\left ( \color{#FF6800}{ x } \color{#FF6800}{ - } \color{#FF6800}{ 3 } \right ) \left ( \color{#FF6800}{ x } \color{#FF6800}{ - } \color{#FF6800}{ 1 } \right ) \left ( \color{#FF6800}{ 2 } \color{#FF6800}{ x } \color{#FF6800}{ + } \color{#FF6800}{ 1 } \right )$
Solution search results
search-thumbnail-For numbers $1-5$ in Chain Rule, use the given function $y=\left(5x^{3}-7x^{2}+2x-3\right)^{4}$ 
1. What is u? 
A. $5x^{3}-7x^{2}+2x-3$ C. $\left(5x^{3}-7x^{2}+2x-3\right)^{4}$ 
B. $5x^{3}-7x^{2}+2x+3$ D. $\left(5x^{3}-7x^{2}+2x+3\right)^{4}$ 
2. What is the du or the derivative of u? 
A. $15x^{2}-14x+2$ TE bnn I.0 C. $5x^{2}-7x+2$ 
B. $15x^{3}-14x+2$ D. $15x^{2}-14x+5$ a bns I A 
nrien nottesimiiqo gmivlovi meldog covig orit $an0$ ovio2-gaivlo8 moldor 
8 3. sdt What is $n7$ 12 nol В. 2 ras9 tnion I.nToiuuloa qeie-d goia woy snW.eqsie 
А. 1 0,8 C. С.3 oso atmio D. 4 ga2 1ol ros9 
bn 4. What is $u^{n-1}7$ u"-1?6 9vsd 1edt odmu to ting s bni 
beeol $A.$ $\left(5x^{3}-7x^{2}+2x-3\right)^{4}$ odmun C. $\left(5x^{3}-7x^{2}+2x+3\right)^{4}$ ori siminim 
B. $\left(5x^{3}-7x^{2}+2x-3\right)^{3}$ D. $\left(5x^{3}-7x^{2}+2x+3\right)^{3}$ bebmuod 
8.7
10th-13th grade
Calculus
search-thumbnail-Exercise $9$ 
$\left(y^{1}$ Factorize the following polynomials 
$\left(0\right)2x^{3}-7x^{2}+2x+3$ 
$2$
7th-9th grade
Algebra
Have you found the solution you wanted?
Try again
Try more features at QANDA!
Search by problem image
Ask 1:1 question to TOP class teachers
AI recommend problems and video lecture
apple logogoogle play logo