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Formula
Solve the quadratic equation
Number of solution
Relationship between roots and coefficients
Graph
$y = 2 x ^ { 2 } - 8 x + 16$
$y = 0$
$y$Intercept
$\left ( 0 , 16 \right )$
Minimum
$\left ( 2 , 8 \right )$
Standard form
$y = 2 \left ( x - 2 \right ) ^ { 2 } + 8$
$2x ^{ 2 } -8x+16 = 0$
$\begin{array} {l} x = 2 + 2 i \\ x = 2 - 2 i \end{array}$
Solve quadratic equations using the square root
$\color{#FF6800}{ 2 } \color{#FF6800}{ x } ^ { \color{#FF6800}{ 2 } } \color{#FF6800}{ - } \color{#FF6800}{ 8 } \color{#FF6800}{ x } \color{#FF6800}{ + } \color{#FF6800}{ 16 } = \color{#FF6800}{ 0 }$
 Divide both sides by the coefficient of the leading highest term 
$\color{#FF6800}{ x } ^ { \color{#FF6800}{ 2 } } \color{#FF6800}{ - } \color{#FF6800}{ 4 } \color{#FF6800}{ x } \color{#FF6800}{ + } \color{#FF6800}{ 8 } = \color{#FF6800}{ 0 }$
$\color{#FF6800}{ x } ^ { \color{#FF6800}{ 2 } } \color{#FF6800}{ - } \color{#FF6800}{ 4 } \color{#FF6800}{ x } \color{#FF6800}{ + } \color{#FF6800}{ 8 } = \color{#FF6800}{ 0 }$
 Convert the quadratic expression on the left side to a perfect square format 
$\left ( \color{#FF6800}{ x } \color{#FF6800}{ - } \color{#FF6800}{ 2 } \right ) ^ { \color{#FF6800}{ 2 } } \color{#FF6800}{ + } \color{#FF6800}{ 8 } \color{#FF6800}{ - } \color{#FF6800}{ 2 } ^ { \color{#FF6800}{ 2 } } = \color{#FF6800}{ 0 }$
$\left ( x - 2 \right ) ^ { 2 } \color{#FF6800}{ + } \color{#FF6800}{ 8 } \color{#FF6800}{ - } \color{#FF6800}{ 2 } ^ { \color{#FF6800}{ 2 } } = 0$
 Move the constant to the right side and change the sign 
$\left ( x - 2 \right ) ^ { 2 } = \color{#FF6800}{ - } \color{#FF6800}{ 8 } \color{#FF6800}{ + } \color{#FF6800}{ 2 } ^ { \color{#FF6800}{ 2 } }$
$\left ( x - 2 \right ) ^ { 2 } = - 8 + \color{#FF6800}{ 2 } ^ { \color{#FF6800}{ 2 } }$
 Calculate power 
$\left ( x - 2 \right ) ^ { 2 } = - 8 + \color{#FF6800}{ 4 }$
$\left ( x - 2 \right ) ^ { 2 } = \color{#FF6800}{ - } \color{#FF6800}{ 8 } \color{#FF6800}{ + } \color{#FF6800}{ 4 }$
 Add $- 8$ and $4$
$\left ( x - 2 \right ) ^ { 2 } = \color{#FF6800}{ - } \color{#FF6800}{ 4 }$
$\left ( \color{#FF6800}{ x } \color{#FF6800}{ - } \color{#FF6800}{ 2 } \right ) ^ { \color{#FF6800}{ 2 } } = \color{#FF6800}{ - } \color{#FF6800}{ 4 }$
 Solve quadratic equations using the square root 
$\color{#FF6800}{ x } \color{#FF6800}{ - } \color{#FF6800}{ 2 } = \pm \sqrt{ \color{#FF6800}{ - } \color{#FF6800}{ 4 } }$
$\color{#FF6800}{ x } \color{#FF6800}{ - } \color{#FF6800}{ 2 } = \pm \sqrt{ \color{#FF6800}{ - } \color{#FF6800}{ 4 } }$
 Solve a solution to $x$
$\color{#FF6800}{ x } = \pm \color{#FF6800}{ 2 } \color{#FF6800}{ i } \color{#FF6800}{ + } \color{#FF6800}{ 2 }$
$\color{#FF6800}{ x } = \pm \color{#FF6800}{ 2 } \color{#FF6800}{ i } \color{#FF6800}{ + } \color{#FF6800}{ 2 }$
 Separate the answer 
$\begin{array} {l} \color{#FF6800}{ x } = \color{#FF6800}{ 2 } \color{#FF6800}{ + } \color{#FF6800}{ 2 } \color{#FF6800}{ i } \\ \color{#FF6800}{ x } = \color{#FF6800}{ 2 } \color{#FF6800}{ - } \color{#FF6800}{ 2 } \color{#FF6800}{ i } \end{array}$
$\begin{array} {l} x = 2 + 2 i \\ x = 2 - 2 i \end{array}$
Calculate using the quodratic formula$($Imaginary root solution$)$\color{#FF6800}{ 2 } \color{#FF6800}{ x } ^ { \color{#FF6800}{ 2 } } \color{#FF6800}{ - } \color{#FF6800}{ 8 } \color{#FF6800}{ x } \color{#FF6800}{ + } \color{#FF6800}{ 16 } = \color{#FF6800}{ 0 } $Solve the quadratic equation$ ax^{2}+bx+c=0 $using the quadratic formula$ \dfrac{-b\pm\sqrt{b^{2}-4ac}}{2a}\color{#FF6800}{ x } = \color{#FF6800}{ \dfrac { - \left ( - 4 \right ) \pm \sqrt{ \left ( - 4 \right ) ^ { 2 } - 4 \times 1 \times 8 } } { 2 \times 1 } }x = \dfrac { \color{#FF6800}{ - } \left ( \color{#FF6800}{ - } 4 \right ) \pm \sqrt{ \left ( - 4 \right ) ^ { 2 } - 4 \times 1 \times 8 } } { 2 \times 1 } $Simplify Minus$ x = \dfrac { 4 \pm \sqrt{ \left ( - 4 \right ) ^ { 2 } - 4 \times 1 \times 8 } } { 2 \times 1 }x = \dfrac { 4 \pm \sqrt{ \left ( \color{#FF6800}{ - } \color{#FF6800}{ 4 } \right ) ^ { \color{#FF6800}{ 2 } } - 4 \times 1 \times 8 } } { 2 \times 1 } $Remove negative signs because negative numbers raised to even powers are positive$ x = \dfrac { 4 \pm \sqrt{ 4 ^ { 2 } - 4 \times 1 \times 8 } } { 2 \times 1 }\color{#FF6800}{ x } = \color{#FF6800}{ \dfrac { 4 \pm \sqrt{ 4 ^ { 2 } - 4 \times 1 \times 8 } } { 2 \times 1 } } $Organize the expression$ \color{#FF6800}{ x } = \color{#FF6800}{ \dfrac { 4 \pm \sqrt{ - 16 } } { 2 \times 1 } }x = \dfrac { 4 \pm \sqrt{ \color{#FF6800}{ - } \color{#FF6800}{ 16 } } } { 2 \times 1 } $Organize the part that can be taken out of the radical sign inside the square root symbol$ x = \dfrac { 4 \pm \color{#FF6800}{ 4 } \sqrt{ \color{#FF6800}{ - } \color{#FF6800}{ 1 } } } { 2 \times 1 }x = \dfrac { 4 \pm 4 \sqrt{ \color{#FF6800}{ - } \color{#FF6800}{ 1 } } } { 2 \times 1 } $It is$ \sqrt{-1} = ix = \dfrac { 4 \pm 4 \color{#FF6800}{ i } } { 2 \times 1 }x = \dfrac { 4 \pm 4 i } { 2 \color{#FF6800}{ \times } \color{#FF6800}{ 1 } } $Multiplying any number by 1 does not change the value$ x = \dfrac { 4 \pm 4 i } { \color{#FF6800}{ 2 } }\color{#FF6800}{ x } = \color{#FF6800}{ \dfrac { 4 \pm 4 i } { 2 } } $Separate the answer$ \begin{array} {l} \color{#FF6800}{ x } = \color{#FF6800}{ \dfrac { 4 + 4 i } { 2 } } \\ \color{#FF6800}{ x } = \color{#FF6800}{ \dfrac { 4 - 4 i } { 2 } } \end{array}\begin{array} {l} x = \color{#FF6800}{ \dfrac { 4 + 4 i } { 2 } } \\ x = \dfrac { 4 - 4 i } { 2 } \end{array} $Reduce the fraction$ \begin{array} {l} x = \color{#FF6800}{ 2 } \color{#FF6800}{ + } \color{#FF6800}{ 2 } \color{#FF6800}{ i } \\ x = \dfrac { 4 - 4 i } { 2 } \end{array}\begin{array} {l} x = 2 + 2 i \\ x = \color{#FF6800}{ \dfrac { 4 - 4 i } { 2 } } \end{array} $Reduce the fraction$ \begin{array} {l} x = 2 + 2 i \\ x = \color{#FF6800}{ 2 } \color{#FF6800}{ - } \color{#FF6800}{ 2 } \color{#FF6800}{ i } \end{array} $Do not have the solution$ $Calculate using the quadratic formula$\color{#FF6800}{ 2 } \color{#FF6800}{ x } ^ { \color{#FF6800}{ 2 } } \color{#FF6800}{ - } \color{#FF6800}{ 8 } \color{#FF6800}{ x } \color{#FF6800}{ + } \color{#FF6800}{ 16 } = 0 $Bind the expressions with the common factor$ 2\color{#FF6800}{ 2 } \left ( \color{#FF6800}{ x } ^ { \color{#FF6800}{ 2 } } \color{#FF6800}{ - } \color{#FF6800}{ 4 } \color{#FF6800}{ x } \color{#FF6800}{ + } \color{#FF6800}{ 8 } \right ) = 0\color{#FF6800}{ 2 } \left ( \color{#FF6800}{ x } ^ { \color{#FF6800}{ 2 } } \color{#FF6800}{ - } \color{#FF6800}{ 4 } \color{#FF6800}{ x } \color{#FF6800}{ + } \color{#FF6800}{ 8 } \right ) = \color{#FF6800}{ 0 } $Divide both sides by$ 2\color{#FF6800}{ x } ^ { \color{#FF6800}{ 2 } } \color{#FF6800}{ - } \color{#FF6800}{ 4 } \color{#FF6800}{ x } \color{#FF6800}{ + } \color{#FF6800}{ 8 } = \color{#FF6800}{ 0 }x = \dfrac { \color{#FF6800}{ - } \left ( \color{#FF6800}{ - } 4 \right ) \pm \sqrt{ \left ( - 4 \right ) ^ { 2 } - 4 \times 1 \times 8 } } { 2 \times 1 } $Simplify Minus$ x = \dfrac { 4 \pm \sqrt{ \left ( - 4 \right ) ^ { 2 } - 4 \times 1 \times 8 } } { 2 \times 1 }x = \dfrac { 4 \pm \sqrt{ \left ( \color{#FF6800}{ - } \color{#FF6800}{ 4 } \right ) ^ { \color{#FF6800}{ 2 } } - 4 \times 1 \times 8 } } { 2 \times 1 } $Remove negative signs because negative numbers raised to even powers are positive$ x = \dfrac { 4 \pm \sqrt{ 4 ^ { 2 } - 4 \times 1 \times 8 } } { 2 \times 1 }\color{#FF6800}{ x } = \color{#FF6800}{ \dfrac { 4 \pm \sqrt{ 4 ^ { 2 } - 4 \times 1 \times 8 } } { 2 \times 1 } } $Organize the expression$ \color{#FF6800}{ x } = \color{#FF6800}{ \dfrac { 4 \pm \sqrt{ - 16 } } { 2 } }\color{#FF6800}{ x } = \color{#FF6800}{ \dfrac { 4 \pm \sqrt{ - 16 } } { 2 } } $The square root of a negative number does not exist within the set of real numbers$  $Do not have the solution$  $Do not have the real root$ $Find the number of solutions$\color{#FF6800}{ 2 } \color{#FF6800}{ x } ^ { \color{#FF6800}{ 2 } } \color{#FF6800}{ - } \color{#FF6800}{ 8 } \color{#FF6800}{ x } \color{#FF6800}{ + } \color{#FF6800}{ 16 } = \color{#FF6800}{ 0 } $Determine the number of roots using discriminant,$ D=b^{2}-4ac $from quadratic equation,$ ax^{2}+bx+c=0\color{#FF6800}{ D } = \left ( \color{#FF6800}{ - } \color{#FF6800}{ 8 } \right ) ^ { \color{#FF6800}{ 2 } } \color{#FF6800}{ - } \color{#FF6800}{ 4 } \color{#FF6800}{ \times } \color{#FF6800}{ 2 } \color{#FF6800}{ \times } \color{#FF6800}{ 16 }D = \left ( \color{#FF6800}{ - } \color{#FF6800}{ 8 } \right ) ^ { \color{#FF6800}{ 2 } } - 4 \times 2 \times 16 $Remove negative signs because negative numbers raised to even powers are positive$ D = 8 ^ { 2 } - 4 \times 2 \times 16D = \color{#FF6800}{ 8 } ^ { \color{#FF6800}{ 2 } } - 4 \times 2 \times 16 $Calculate power$ D = \color{#FF6800}{ 64 } - 4 \times 2 \times 16D = 64 \color{#FF6800}{ - } \color{#FF6800}{ 4 } \color{#FF6800}{ \times } \color{#FF6800}{ 2 } \color{#FF6800}{ \times } \color{#FF6800}{ 16 } $Multiply the numbers$ D = 64 \color{#FF6800}{ - } \color{#FF6800}{ 128 }D = \color{#FF6800}{ 64 } \color{#FF6800}{ - } \color{#FF6800}{ 128 } $Subtract$ 128 $from$ 64D = \color{#FF6800}{ - } \color{#FF6800}{ 64 }\color{#FF6800}{ D } = \color{#FF6800}{ - } \color{#FF6800}{ 64 } $Since$ D<0 $, there is no real root of the following quadratic equation$  $Do not have the real root$ \alpha + \beta = 4 , \alpha \beta = 8$Find the sum and product of the two roots of the quadratic equation$\color{#FF6800}{ 2 } \color{#FF6800}{ x } ^ { \color{#FF6800}{ 2 } } \color{#FF6800}{ - } \color{#FF6800}{ 8 } \color{#FF6800}{ x } \color{#FF6800}{ + } \color{#FF6800}{ 16 } = \color{#FF6800}{ 0 } $In the quadratic equation$ ax^{2}+bx+c=0 $, if the two roots are$ \alpha, \beta $, then it is$ \alpha + \beta =-\dfrac{b}{a} $,$ \alpha\times\beta=\dfrac{c}{a}\color{#FF6800}{ \alpha } \color{#FF6800}{ + } \color{#FF6800}{ \beta } = \color{#FF6800}{ - } \color{#FF6800}{ \dfrac { - 8 } { 2 } } , \color{#FF6800}{ \alpha } \color{#FF6800}{ \beta } = \color{#FF6800}{ \dfrac { 16 } { 2 } }\alpha + \beta = \color{#FF6800}{ - } \color{#FF6800}{ \dfrac { - 8 } { 2 } } , \alpha \beta = \dfrac { 16 } { 2 } $Solve the sign of a fraction with a negative sign$ \alpha + \beta = \color{#FF6800}{ \dfrac { 8 } { 2 } } , \alpha \beta = \dfrac { 16 } { 2 }\alpha + \beta = \color{#FF6800}{ \dfrac { 8 } { 2 } } , \alpha \beta = \dfrac { 16 } { 2 } $Reduce the fraction$ \alpha + \beta = \color{#FF6800}{ 4 } , \alpha \beta = \dfrac { 16 } { 2 }\alpha + \beta = 4 , \alpha \beta = \color{#FF6800}{ \dfrac { 16 } { 2 } } $Reduce the fraction$ \alpha + \beta = 4 , \alpha \beta = \color{#FF6800}{ 8 }\$
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