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Formula
Solve the equation
Answer
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Graph
$y = 2 - x$
$y = x - 8$
$x$-intercept
$\left ( 2 , 0 \right )$
$y$-intercept
$\left ( 0 , 2 \right )$
$x$-intercept
$\left ( 8 , 0 \right )$
$y$-intercept
$\left ( 0 , - 8 \right )$
$2-x = x-8$
$x = 5$
$ $ Solve a solution to $ x$
$\color{#FF6800}{ 2 } \color{#FF6800}{ - } \color{#FF6800}{ x } = x - 8$
$ $ Organize the expression $ $
$\color{#FF6800}{ - } \color{#FF6800}{ x } \color{#FF6800}{ + } \color{#FF6800}{ 2 } = x - 8$
$- x + 2 = \color{#FF6800}{ x } - 8$
$ $ Move the variable to the left-hand side and change the symbol $ $
$- x + 2 \color{#FF6800}{ - } \color{#FF6800}{ x } = - 8$
$- x \color{#FF6800}{ + } \color{#FF6800}{ 2 } - x = - 8$
$ $ Move the constant to the right side and change the sign $ $
$- x - x = - 8 \color{#FF6800}{ - } \color{#FF6800}{ 2 }$
$\color{#FF6800}{ - } \color{#FF6800}{ x } \color{#FF6800}{ - } \color{#FF6800}{ x } = - 8 - 2$
$ $ Organize the expression $ $
$\color{#FF6800}{ - } \color{#FF6800}{ 2 } \color{#FF6800}{ x } = - 8 - 2$
$- 2 x = \color{#FF6800}{ - } \color{#FF6800}{ 8 } \color{#FF6800}{ - } \color{#FF6800}{ 2 }$
$ $ Find the sum of the negative numbers $ $
$- 2 x = \color{#FF6800}{ - } \color{#FF6800}{ 10 }$
$\color{#FF6800}{ - } \color{#FF6800}{ 2 } \color{#FF6800}{ x } = \color{#FF6800}{ - } \color{#FF6800}{ 10 }$
$ $ Change the sign of both sides of the equation $ $
$2 x = 10$
$\color{#FF6800}{ 2 } \color{#FF6800}{ x } = \color{#FF6800}{ 10 }$
$ $ Divide both sides by the same number $ $
$\color{#FF6800}{ x } = \color{#FF6800}{ 5 }$
$ $ 그래프 보기 $ $
Graph
Solution search results
search-thumbnail-Limit $\sqrt{13-2} x-3$ 
$\left(2$ $2-x$
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search-thumbnail-Which of the following rational expressions is in its simplest form? 
$0$ $A$ A. $\dfrac {z\left(x-2y\right)} {2y-x}$ 
$\square $ $B$ $\dfrac {x^{3}-8} {2-x}$ 
$3C.$ $\dfrac {7x^{2}y^{4}} {28x^{3}y^{3}}$ 
$0$ $\square $ $\dfrac {t+6y} {t+2y}$
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search-thumbnail-$8$ $3x^{2}+14x-8$ 
$→\right)$
10th-13th grade
Other
search-thumbnail-$2-x=x-8$
7th-9th grade
Other
search-thumbnail-$8^{2}=x=2$
10th-13th grade
Other
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