Calculator search results

Formula
Calculate the value
Answer
circle-check-icon
$2+ \sqrt{ 5 } +2- \sqrt{ 5 }$
$4$
Calculate the value
$2 \color{#FF6800}{ + } \sqrt{ \color{#FF6800}{ 5 } } + 2 \color{#FF6800}{ - } \sqrt{ \color{#FF6800}{ 5 } }$
$ $ Remove the two numbers if the values are the same and the signs are different $ $
$2 + 2$
$\color{#FF6800}{ 2 } \color{#FF6800}{ + } \color{#FF6800}{ 2 }$
$ $ Add $ 2 $ and $ 2$
$\color{#FF6800}{ 4 }$
Solution search results
search-thumbnail-What is the inverse of $g\left(x\right)=\sqrt{x-1} $ $Og\left(x\right)=\sqrt{x+1} $ $+1$ $g^{'}\left(x\right)=5-$ $y_{9}$ $g\sqrt{ef\left(x\left(nght\right)} =\left(f_{tac\left(x+1\right)0sq\pi \left(x\right)}$ $Og^{'}\left(x\right)=x^{2}+1$ $○g\left(x\right)=x^{2}-1$ « Previous Ne
Other
Check solution
search-thumbnail-What is the inverse of $g\left(x\right)=\sqrt{x-1} $ $Og\left(x\right)=\sqrt{x+1} $ $+1$ $g^{'}\left(x\right)=5-$ $y_{9}$ $g\sqrt{ef\left(x\left(nght\right)} =\left(f_{tac\left(x+1\right)0sq\pi \left(x\right)}$ $Og^{'}\left(x\right)=x^{2}+1$ $○g\left(x\right)=x^{2}-1$ « Previous Ne
Other
Check solution
search-thumbnail-$\dfrac {2+\sqrt{5} } {2-\sqrt{5} }$ $+2-\sqrt{5} $ $2-\sqrt{5} $ $-$ $-$ $2+\sqrt{5} $
10th-13th grade
Other
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search-thumbnail-$\bar{5} +2-$ $10+5=$
1st-6th grade
Algebra
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search-thumbnail-The rationalizing factor of \sqrt{23} is $°$ $Options^{°}$ $0$ A 24 23 C \sqrt{23} D None of these
7th-9th grade
Other
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