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Expand the expression
Answer
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Factorize the expression
Answer
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$2 \left( x-y \right) + \left( a+3b \right) \left( x-y \right)$
$\left ( a + 3 b + 2 \right ) x + \left ( - a - 3 b - 2 \right ) y$
Organize polynomials
$\color{#FF6800}{ 2 } \left ( \color{#FF6800}{ x } \color{#FF6800}{ - } \color{#FF6800}{ y } \right ) + \left ( a + 3 b \right ) \left ( x - y \right )$
$ $ Organize the expression with the distributive law $ $
$\color{#FF6800}{ 2 } \color{#FF6800}{ x } \color{#FF6800}{ - } \color{#FF6800}{ 2 } \color{#FF6800}{ y } + \left ( a + 3 b \right ) \left ( x - y \right )$
$2 x - 2 y + \left ( \color{#FF6800}{ a } \color{#FF6800}{ + } \color{#FF6800}{ 3 } \color{#FF6800}{ b } \right ) \left ( \color{#FF6800}{ x } \color{#FF6800}{ - } \color{#FF6800}{ y } \right )$
$ $ Organize the expression with the distributive law $ $
$2 x - 2 y + \left ( \color{#FF6800}{ a } \color{#FF6800}{ + } \color{#FF6800}{ 3 } \color{#FF6800}{ b } \right ) \color{#FF6800}{ x } + \left ( \color{#FF6800}{ - } \color{#FF6800}{ a } \color{#FF6800}{ - } \color{#FF6800}{ 3 } \color{#FF6800}{ b } \right ) \color{#FF6800}{ y }$
$\color{#FF6800}{ 2 } \color{#FF6800}{ x } \color{#FF6800}{ - } \color{#FF6800}{ 2 } \color{#FF6800}{ y } \color{#FF6800}{ + } \left ( \color{#FF6800}{ a } \color{#FF6800}{ + } \color{#FF6800}{ 3 } \color{#FF6800}{ b } \right ) \color{#FF6800}{ x } \color{#FF6800}{ + } \left ( \color{#FF6800}{ - } \color{#FF6800}{ a } \color{#FF6800}{ - } \color{#FF6800}{ 3 } \color{#FF6800}{ b } \right ) \color{#FF6800}{ y }$
$ $ Organize the similar terms $ $
$\left ( \color{#FF6800}{ 2 } \color{#FF6800}{ + } \left ( \color{#FF6800}{ a } \color{#FF6800}{ + } \color{#FF6800}{ 3 } \color{#FF6800}{ b } \right ) \right ) \color{#FF6800}{ x } \color{#FF6800}{ + } \left ( \color{#FF6800}{ - } \color{#FF6800}{ 2 } \color{#FF6800}{ + } \left ( \color{#FF6800}{ - } \color{#FF6800}{ a } \color{#FF6800}{ - } \color{#FF6800}{ 3 } \color{#FF6800}{ b } \right ) \right ) \color{#FF6800}{ y }$
$\left ( \color{#FF6800}{ 2 } \color{#FF6800}{ + } \left ( \color{#FF6800}{ a } \color{#FF6800}{ + } \color{#FF6800}{ 3 } \color{#FF6800}{ b } \right ) \right ) \color{#FF6800}{ x } + \left ( - 2 + \left ( - a - 3 b \right ) \right ) y$
$ $ Arrange the constant term $ $
$\left ( \color{#FF6800}{ a } \color{#FF6800}{ + } \color{#FF6800}{ 3 } \color{#FF6800}{ b } \color{#FF6800}{ + } \color{#FF6800}{ 2 } \right ) \color{#FF6800}{ x } + \left ( - 2 + \left ( - a - 3 b \right ) \right ) y$
$\left ( a + 3 b + 2 \right ) x + \left ( \color{#FF6800}{ - } \color{#FF6800}{ 2 } \color{#FF6800}{ + } \left ( \color{#FF6800}{ - } \color{#FF6800}{ a } \color{#FF6800}{ - } \color{#FF6800}{ 3 } \color{#FF6800}{ b } \right ) \right ) \color{#FF6800}{ y }$
$ $ Arrange the constant term $ $
$\left ( a + 3 b + 2 \right ) x + \left ( \color{#FF6800}{ - } \color{#FF6800}{ a } \color{#FF6800}{ - } \color{#FF6800}{ 3 } \color{#FF6800}{ b } \color{#FF6800}{ - } \color{#FF6800}{ 2 } \right ) \color{#FF6800}{ y }$
$\left ( x - y \right ) \left ( a + 3 b + 2 \right )$
Arrange the expression in the form of factorization..
$\color{#FF6800}{ 2 } \left ( \color{#FF6800}{ x } \color{#FF6800}{ - } \color{#FF6800}{ y } \right ) \color{#FF6800}{ + } \left ( \color{#FF6800}{ a } \color{#FF6800}{ + } \color{#FF6800}{ 3 } \color{#FF6800}{ b } \right ) \left ( \color{#FF6800}{ x } \color{#FF6800}{ - } \color{#FF6800}{ y } \right )$
$ $ Expand the expression $ $
$\left ( \color{#FF6800}{ a } \color{#FF6800}{ + } \color{#FF6800}{ 3 } \color{#FF6800}{ b } \color{#FF6800}{ + } \color{#FF6800}{ 2 } \right ) \color{#FF6800}{ x } \color{#FF6800}{ + } \left ( \color{#FF6800}{ - } \color{#FF6800}{ a } \color{#FF6800}{ - } \color{#FF6800}{ 3 } \color{#FF6800}{ b } \color{#FF6800}{ - } \color{#FF6800}{ 2 } \right ) \color{#FF6800}{ y }$
$\left ( \color{#FF6800}{ a } \color{#FF6800}{ + } \color{#FF6800}{ 3 } \color{#FF6800}{ b } \color{#FF6800}{ + } \color{#FF6800}{ 2 } \right ) \color{#FF6800}{ x } \color{#FF6800}{ + } \left ( \color{#FF6800}{ - } \color{#FF6800}{ a } \color{#FF6800}{ - } \color{#FF6800}{ 3 } \color{#FF6800}{ b } \color{#FF6800}{ - } \color{#FF6800}{ 2 } \right ) \color{#FF6800}{ y }$
$ $ Do factorization $ $
$\left ( \color{#FF6800}{ x } \color{#FF6800}{ - } \color{#FF6800}{ y } \right ) \left ( \color{#FF6800}{ a } \color{#FF6800}{ + } \color{#FF6800}{ 3 } \color{#FF6800}{ b } \color{#FF6800}{ + } \color{#FF6800}{ 2 } \right )$
Solution search results
search-thumbnail-Theis the statement of the Mean Value Theorem from your te\timestb00k
The is the statement of the Mean Value Theorem from your $te\times tb00k$ $Tneoren$ $m4.5$ $Ne8n$ Value Theorem Let f be continuous over $leclose$ interval $\left(a.b\right)aod$ $i$ $eo$ $xd$ $csnlc$ $\left(ab\right)$ $mmd$ exists at least one point cE $\left(a.b\right)$ $si1dhtba$ $f^{'}\left(c\right)=\dfrac {f\left(b\right)-f\left(a\right)} {b-a}$ What is the geometric interpretation of the conclusion of the theorem? O The tangent line to the graph of \(f\left(x\right)\) at $l\left(c1\right)$ is parallel to the secant line connecting \(\left(a,f\left(a\right)\right)\) and \(\left(b,f\left(b\right)\right)\). O The tangent line to the graph of $\left(f\left(lef\left(x\left(right\right)$ at \(c\) is the secant line connecting \(\left(a,f\left(a\right)\right)\) $ana$ \(\left(b,f\left(b\right)\right)\). O The tangent line to the graph $of$ $\left(f\left(leF\left(x\left(right\right)\left(\right)at1\left(c1\right)is$ perpendicular to the secant line connecting \(\left(a,f\left(a\right)\right)\) and A(\left(b,f\left(b\right)\right)\). O The tangent line to the graph of $\left(fleH\left(x\right)nght\right)\right)\right)$ $at$ $\left(c\right)\right)ishoizonta|$ $Tnere$ is more than one tangent line to the graph $0no$ $\left(flcf\left(x\right)night\right)\left($ $at1\left(c1\right)$
Calculus
Search count: 3,278
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search-thumbnail-If the sum of two consecutive
If the sum of two consecutive numbers is $45$ and one number is $X$ .This statement in the form of equation $1s:$ $\left(1$ Point) $\right)$ $○5x+1$ $1eft\left(x+1$ $r1gnt\right)=45s$ $○sx+1ef\left(x+2$ $r1gnt\right)=145s$ $sx+1x=45s$
7th-9th grade
Algebra
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search-thumbnail-$The\ reciprocal\\ 0+11) \left(\frac{2}
$8$ $\left(1$ Point) $1\right)$ The\ reciprocal\\ $0+11\right)$ \left(\frac{2} $c\left(2\right)$ {5}\right)^0\ $\right)$ \ $1111s\right)$ $S$ $S1S$ $s3S$ $S4S$ $s2S$
7th-9th grade
Other
Search count: 4,895
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