Calculator search results

Find the difference

Answer

$\dfrac { 43 } { 24 }$

Find the difference

$\color{#FF6800}{ 2 \dfrac { \color{#FF6800}{ 7 } } { \color{#FF6800}{ 8 } } } - 1 \dfrac { 1 } { 12 }$

$ $ Convert mixed number into improper fraction $ $

$\color{#FF6800}{ \dfrac { \color{#FF6800}{ 23 } } { \color{#FF6800}{ 8 } } } - 1 \dfrac { 1 } { 12 }$

$\dfrac { 23 } { 8 } \color{#FF6800}{ - } \color{#FF6800}{ 1 \dfrac { \color{#FF6800}{ 1 } } { \color{#FF6800}{ 12 } } }$

$ $ Convert mixed number into improper fraction $ $

$\dfrac { 23 } { 8 } \color{#FF6800}{ - } \color{#FF6800}{ \dfrac { \color{#FF6800}{ 13 } } { \color{#FF6800}{ 12 } } }$

$\dfrac { 23 } { \color{#FF6800}{ 8 } } - \dfrac { 13 } { \color{#FF6800}{ 12 } }$

$ $ The smallest common multiple in denominator is $ 24$

$\dfrac { 23 } { \color{#FF6800}{ 8 } } - \dfrac { 13 } { \color{#FF6800}{ 12 } }$

$\dfrac { 23 } { 8 } - \dfrac { 13 } { 12 }$

$ $ Multiply the denominator and the numerator so that the denominator is the smallest common multiple $ $

$\dfrac { 23 \times \color{#FF6800}{ 3 } } { 8 \times \color{#FF6800}{ 3 } } - \dfrac { 13 \times \color{#FF6800}{ 2 } } { 12 \times \color{#FF6800}{ 2 } }$

$\color{#FF6800}{ \dfrac { \color{#FF6800}{ 23 } \color{#FF6800}{ \times } \color{#FF6800}{ 3 } } { \color{#FF6800}{ 8 } \color{#FF6800}{ \times } \color{#FF6800}{ 3 } } } \color{#FF6800}{ - } \color{#FF6800}{ \dfrac { \color{#FF6800}{ 13 } \color{#FF6800}{ \times } \color{#FF6800}{ 2 } } { \color{#FF6800}{ 12 } \color{#FF6800}{ \times } \color{#FF6800}{ 2 } } }$

$ $ Organize the expression $ $

$\color{#FF6800}{ \dfrac { \color{#FF6800}{ 69 } } { \color{#FF6800}{ 24 } } } \color{#FF6800}{ - } \color{#FF6800}{ \dfrac { \color{#FF6800}{ 26 } } { \color{#FF6800}{ 24 } } }$

$\color{#FF6800}{ \dfrac { \color{#FF6800}{ 69 } } { \color{#FF6800}{ 24 } } } \color{#FF6800}{ - } \color{#FF6800}{ \dfrac { \color{#FF6800}{ 26 } } { \color{#FF6800}{ 24 } } }$

$ $ Since the denominator is the same as $ 24 $ , combine the fractions into one $ $

$\color{#FF6800}{ \dfrac { \color{#FF6800}{ 69 } \color{#FF6800}{ - } \color{#FF6800}{ 26 } } { \color{#FF6800}{ 24 } } }$

$\dfrac { \color{#FF6800}{ 69 } \color{#FF6800}{ - } \color{#FF6800}{ 26 } } { 24 }$

$ $ Subtract $ 26 $ from $ 69$

$\dfrac { \color{#FF6800}{ 43 } } { 24 }$

Solution search results

search-thumbnail-Which of the following rational numbers are

Which of the following rational numbers are equivalent? $0Ptionsy$ A \frac{5}{6}, \frac{30}{36} B $s\sqrt{rac\left(} -2\right)\left(3\right)\sqrt{1rac} \sqrt{4\right)16\right)4} $ C $s\sqrt{11aC\left(} -4\right)1-7b,\sqrt{1rac\left(16\sqrt{35\right)9} } $ D \frac{1}{2},\frac{3}{8}

7th-9th grade

Other

Search count: 5,909

search-thumbnail-Can you answer this?

Can you answer this? $20$ $25$ $18$ $\left($ $\left(A\right)$ $A\right)2$ $21frac\left(5\right)\left(9\right)$ \) $\left(B\right)$ $B\right)$ $1\left(211$ $\left(C\right)$ $1\left(21$ $21+rac\left(7\right)+9\right)$ \) $\left(D\right)$ $1\left(2\right)$ 2\frac{8}{9} $ac\left(8\right)\left(9\right)$ \) $9:18PM\sqrt{} $

1st-6th grade

Algebra

Search count: 1,480

$search-thumbnail-Using the \emph{removal of first derivative}$

Using the \emph{removal of first derivative} method, the differential equation \( \frac{d^{2}y} $\left(d\times n$ $\left(2\right)\right)+P|ffac\left(dy\right)\left(dx\right)+Qy=F$ $dx\right)+Qy=RN\right)$ is transformed as \). For, the differential equation \frac{d^{2}y} $\left(d^{n}\left(2\right)y\right)$ $dx$ $\left(2\right)+2x$ $\left(0C\left(dy\right)\left(dx\right)+\left(x$ $2+1\right)y=\times n3+3x\right)$ the value of $\left(11\right)$

Calculus

Search count: 3,465

$search-thumbnail-(int|imits -0a1(1-\timesn_{2}{)_{3}}^{n}$

$\left(int|imits$ $-0a1\left(1-\times n_{2}{\right)_{3}}^{n}$ $x^{A}3dx=7\right)$ $\left($ $frac\left(1\right)\left(40\right)\right)$ $\left($ $\left(troc\left(1\right)\left(35\right)\right)$ $\left(troc\left(1\right)\left(30\right)\right)$ $\left(tr0c\left(1\right)\left(25\right)\right)$

Calculus

search-thumbnail-In the following problem a,b, b,and represent REAL NUMBERS.

In the following problem $a,b,$ b,and c represent REAL NUMBERS. The derivative of $g\left(x\right)=log _{a}\left(bx\right)+cx^{2}is$ $○$ $g^{1}\left(x\right)=\right)dfrac\left(b\right)log _{-}a\left(bx\right)\right)\left(N1n$ $a\right)+2cx1\right)$ $○$ $\left(g\left(x\right)=\right)dtracb$ $loga\left(bx\right)+2c\times \right)Nln$ a}\) $○$ $g^{'}\left(x\right)=\left(dfraC\left(a\right)log _{-}a\left(bx\right)\right)\left(ln$ $\right)+2c\times 1\right)\right)$ $○$ $g^{1}\left(x\right)=\left(dfrac\left(b$ $log _{-}a\left(bx\right)\right)\left(ln$ $a1\right)$ $○$ $\left(\left(g^{1}\left(x\right)=b$ $log _{-}a\left(bx\right)+2cx1\right)$ $○$ $g\left(x\right)=\left(dfrac\left(b$ $log _{-}a\left(bx\right)\right)\left(1ln$ $a|+2c1\right)$

Calculus

$search-thumbnail-Solve the : 0<θ<90^{°}$

$11.$ Question $11$ Solve the $:$ $folloMlng'$ $0<θ<90^{°}$ $\left(1\right)$ $2sin^{2}θ=1\right)$ $\left(rac\left(3\right)\left(2\right)\right)$ $\left(11\right)$ $3tan^{2}θ+2=3$ $\left(111\right)cos^{2}θ$ $11rac\left(1\right)\left(4\right)\right)=$ $c\left(1\right)\left(4\right)\right)=11113c\left(1\right)\left(2\right)\right)$

10th-13th grade

Trigonometry

Have you found the solution you wanted?

Try more features at Qanda!

Search by problem image

Ask 1:1 question to TOP class teachers

AI recommend problems and video lecture

© 2021 Mathpresso Inc.

|

CEO Jongheun Lee, Yongjae Lee

|

17th Floor, WeWork Seolleung Station III, 428, Seolleung-ro, Gangnam-gu, Seoul

|

EMAIL support.en@mathpresso.com