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Formula
Find the difference
Answer
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$2 \dfrac{ 5 }{ 16 } - \dfrac{ 7 }{ 24 }$
$\dfrac { 97 } { 48 }$
Find the difference
$\color{#FF6800}{ 2 \dfrac { 5 } { 16 } } - \dfrac { 7 } { 24 }$
$ $ Convert mixed number into improper fraction $ $
$\color{#FF6800}{ \dfrac { 37 } { 16 } } - \dfrac { 7 } { 24 }$
$\dfrac { 37 } { \color{#FF6800}{ 16 } } - \dfrac { 7 } { \color{#FF6800}{ 24 } }$
$ $ The smallest common multiple in denominator is $ 48$
$\dfrac { 37 } { \color{#FF6800}{ 16 } } - \dfrac { 7 } { \color{#FF6800}{ 24 } }$
$\dfrac { 37 } { 16 } - \dfrac { 7 } { 24 }$
$ $ Multiply the denominator and the numerator so that the denominator is the smallest common multiple $ $
$\dfrac { 37 \times \color{#FF6800}{ 3 } } { 16 \times \color{#FF6800}{ 3 } } - \dfrac { 7 \times \color{#FF6800}{ 2 } } { 24 \times \color{#FF6800}{ 2 } }$
$\color{#FF6800}{ \dfrac { 37 \times 3 } { 16 \times 3 } } \color{#FF6800}{ - } \color{#FF6800}{ \dfrac { 7 \times 2 } { 24 \times 2 } }$
$ $ Organize the expression $ $
$\color{#FF6800}{ \dfrac { 111 } { 48 } } \color{#FF6800}{ - } \color{#FF6800}{ \dfrac { 14 } { 48 } }$
$\color{#FF6800}{ \dfrac { 111 } { 48 } } \color{#FF6800}{ - } \color{#FF6800}{ \dfrac { 14 } { 48 } }$
$ $ Since the denominator is the same as $ 48 $ , combine the fractions into one $ $
$\color{#FF6800}{ \dfrac { 111 - 14 } { 48 } }$
$\dfrac { \color{#FF6800}{ 111 } \color{#FF6800}{ - } \color{#FF6800}{ 14 } } { 48 }$
$ $ Subtract $ 14 $ from $ 111$
$\dfrac { \color{#FF6800}{ 97 } } { 48 }$
Solution search results
search-thumbnail-Can you answer this? 
$20$ $25$ 

$18$ 

$\left($ 
$\left(A\right)$ $A\right)2$ 
$21frac\left(5\right)\left(9\right)$ \) 
$\left(B\right)$ $B\right)$ $1\left(211$ 
$\left(C\right)$ $1\left(21$ $21+rac\left(7\right)+9\right)$ \) 
$\left(D\right)$ $1\left(2\right)$ 2\frac{8}{9} 
$ac\left(8\right)\left(9\right)$ \) $9:18PM\sqrt{} $
1st-6th grade
Algebra
search-thumbnail-$1.$ Simplify: 
$\left(1\right)$ $\dfrac {2} {3}+\left(\dfrac {-5} {9}\right)+\dfrac {7} {6}$ (b) $1$ $\dfrac {-5} {12}+\dfrac {5} {-18}-\dfrac {7} {24}$ $\left(c\right)$ $\dfrac {-8} {9}-\dfrac {4} {15}+\left(\dfrac {-3} {20}\right)$ (d) $-4+\dfrac {21} {16}-\dfrac {10} {24}$ 
$2z$ Simplify and express in the form $q$ 
$\left(3\right)$ $\dfrac {4} {3}+\dfrac {3} {5}+\left(\dfrac {-2} {3}\right)+\left(\dfrac {-11} {5}\right)$ $\left(b\right)$ $\dfrac {-11} {12}+\dfrac {1} {4}-0+\dfrac {3} {-8}-\dfrac {1} {2}$ $c\right)$ $\dfrac {-2} {3}-\dfrac {5} {6}+\dfrac {7} {24}-\left(\dfrac {-13} {-36}\right)$
7th-9th grade
Other
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