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Solve the equation
Answer
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$y = 16 + 7 x - 5 + x$
$y = 11 x - 3 - x$
$x$Intercept
$\left ( - \dfrac { 11 } { 8 } , 0 \right )$
$y$Intercept
$\left ( 0 , 11 \right )$
$x$Intercept
$\left ( \dfrac { 3 } { 10 } , 0 \right )$
$y$Intercept
$\left ( 0 , - 3 \right )$
$16+7x-5+x = 11x-3-x$
$x = 7$
$ $ Solve a solution to $ x$
$\color{#FF6800}{ 16 } \color{#FF6800}{ + } \color{#FF6800}{ 7 } \color{#FF6800}{ x } \color{#FF6800}{ - } \color{#FF6800}{ 5 } \color{#FF6800}{ + } \color{#FF6800}{ x } = \color{#FF6800}{ 11 } \color{#FF6800}{ x } \color{#FF6800}{ - } \color{#FF6800}{ 3 } \color{#FF6800}{ - } \color{#FF6800}{ x }$
$ $ Organize the expression $ $
$\color{#FF6800}{ 11 } \color{#FF6800}{ + } \color{#FF6800}{ 8 } \color{#FF6800}{ x } = \color{#FF6800}{ 10 } \color{#FF6800}{ x } \color{#FF6800}{ - } \color{#FF6800}{ 3 }$
$\color{#FF6800}{ 11 } \color{#FF6800}{ + } \color{#FF6800}{ 8 } \color{#FF6800}{ x } = 10 x - 3$
$ $ Organize the expression $ $
$\color{#FF6800}{ 8 } \color{#FF6800}{ x } \color{#FF6800}{ + } \color{#FF6800}{ 11 } = 10 x - 3$
$\color{#FF6800}{ 8 } \color{#FF6800}{ x } \color{#FF6800}{ + } \color{#FF6800}{ 11 } = \color{#FF6800}{ 10 } \color{#FF6800}{ x } \color{#FF6800}{ - } \color{#FF6800}{ 3 }$
$ $ Organize the expression $ $
$\color{#FF6800}{ 8 } \color{#FF6800}{ x } \color{#FF6800}{ - } \color{#FF6800}{ 10 } \color{#FF6800}{ x } = \color{#FF6800}{ - } \color{#FF6800}{ 3 } \color{#FF6800}{ - } \color{#FF6800}{ 11 }$
$\color{#FF6800}{ 8 } \color{#FF6800}{ x } \color{#FF6800}{ - } \color{#FF6800}{ 10 } \color{#FF6800}{ x } = - 3 - 11$
$ $ Organize the expression $ $
$\color{#FF6800}{ - } \color{#FF6800}{ 2 } \color{#FF6800}{ x } = - 3 - 11$
$\color{#FF6800}{ - } \color{#FF6800}{ 2 } \color{#FF6800}{ x } = \color{#FF6800}{ - } \color{#FF6800}{ 3 } \color{#FF6800}{ - } \color{#FF6800}{ 11 }$
$ $ Organize the expression $ $
$\color{#FF6800}{ 2 } \color{#FF6800}{ x } = \color{#FF6800}{ 14 }$
$\color{#FF6800}{ 2 } \color{#FF6800}{ x } = \color{#FF6800}{ 14 }$
$ $ Divide both sides by the same number $ $
$\color{#FF6800}{ x } = \color{#FF6800}{ 7 }$
$ $ 그래프 보기 $ $
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$3.$ Giải các phương trình 
a) $\sqrt{x-5} +x=\sqrt{x-5} +6$ 
c) $\right)$ $\dfrac {x^{2}} {\sqrt{x-2} }=\dfrac {8} {\sqrt{x-2} }$ $i$ 
$4.$ Giải các phương trình 
a) $\right)$ $3x+4$ $1$ $--$ $4$ $=-+3$ 
$=$
10th-13th grade
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