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Formula
Factorize the expression
Answer
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$15y ^{ 3 } +20y ^{ 2 } -5y$
$5 y \left ( 3 y ^ { 2 } + 4 y - 1 \right )$
Arrange the expression in the form of factorization..
$\color{#FF6800}{ 15 } \color{#FF6800}{ y } ^ { \color{#FF6800}{ 3 } } \color{#FF6800}{ + } \color{#FF6800}{ 20 } \color{#FF6800}{ y } ^ { \color{#FF6800}{ 2 } } \color{#FF6800}{ - } \color{#FF6800}{ 5 } \color{#FF6800}{ y }$
$ $ Bind the expressions with the common factor $ 5 y$
$\color{#FF6800}{ 5 } \color{#FF6800}{ y } \left ( \color{#FF6800}{ 3 } \color{#FF6800}{ y } ^ { \color{#FF6800}{ 2 } } \color{#FF6800}{ + } \color{#FF6800}{ 4 } \color{#FF6800}{ y } \color{#FF6800}{ - } \color{#FF6800}{ 1 } \right )$
Solution search results
search-thumbnail-FACTORIZAR los SIGUIENTES 
$e_{JEPClcos:}$ 
$°$ $15y^{3}$ $+20y^{2}-5y$ 
$2a^{2}x-5a^{2}y+15by-6by$ 
$°$ $16-10yx^{2}$ $+169x^{4}$ 
$0$ $361x^{14}-1$ 
$.x^{2}+14\times +13$ 
$0$ $15a^{2}-8a-12$
7th-9th grade
Algebra
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