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Formula
Divide the numbers
Answer
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Find the quotient and the remainder
Answer
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$1024 \div 8$
$128$
Divide the numbers
$\color{#FF6800}{ 1024 } \color{#FF6800}{ \div } \color{#FF6800}{ 8 }$
$ $ Divide $ 1024 $ by $ 8$
$\color{#FF6800}{ 128 }$
$ $ Quotient $ : 128 \\ $ Remainder $ : 0$
Find the quotient and the remainder
$\color{#FF6800}{ 1024 } \color{#FF6800}{ \div } \color{#FF6800}{ 8 }$
$ $ Find the quotient and the remainder $ $
$ $ Quotient $ : 128 \\ $ Remainder $ : 0$
Solution search results
search-thumbnail-$20.$ $1$ $\left(0.01024\longdiv{5}$
10th-13th grade
Other
search-thumbnail-Which is the graph of the solution set $of-2x+5y>157$ 
$101y$ $10|^{y}$ $10fy$ 
$8$ $8$ $8$ 

6. 
$42$ $4$ $2$ $=4$ $4$ 
$2$ 
$2$ 

$2468$ 8 $10$ 2 4 $68$ 10 2 $46$ 8 $10$
10th-13th grade
Other
search-thumbnail-$\left(077$ 
$19.$ Evaluate, $3$ $\left(0.01024$ $\longdiv{5}$ (b) $0.064$ 
(a) $0.014$ $\left($ (d) $0.091$ 
$-\left(c\right)$ $0.075$
7th-9th grade
Other
search-thumbnail-16. V8 
a. (8)2 b. (4)z c. (8) d. (4) 
$17.\sqrt [3] {120} $ 
a. (120)z b. (120) c. $1$ $\left(120\longdiv{4}$ d. $1$ $\left(120$ $\longdiv{5}$ 
$18.\sqrt [3] {\left(x+y\right)^{2}} $ 
$a.\left(x+y^{2}$ $\longdiv{3}$ b. $\left(x+y^{3}$ $\longdiv{2}$ $1$ $c.\left(x+y\longdiv{3}$ d. $1$ $\left(x+y\longdiv{2}$ 
$19.\sqrt [4] {\left(4x+2y\right)^{3}} $ 
$2$ $a.\left(4x+2y\longdiv{3}$ b. $\left(4x+2y\right)\dfrac {3} {4}$ $c.\left(4x+2y^{4}$ $\longdiv{3}$ d. $\left(4x+2$ 
$20.\sqrt [5] {\left(1024\right)^{2}} $ 
a. $1$ $\left(1024$ $\longdiv{5}$ b. $5$ $\left(1024\longdiv{2}$ c. $2$ $\left(1024\longdiv{5}$ d. $\left(1024\right)$
7th-9th grade
Algebra
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