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Find the difference

Answer

$\dfrac { 187 } { 100 }$

Find the difference

$\color{#FF6800}{ 10 \dfrac { \color{#FF6800}{ 3 } } { \color{#FF6800}{ 20 } } } - 8 \dfrac { 7 } { 25 }$

$ $ Convert mixed number into improper fraction $ $

$\color{#FF6800}{ \dfrac { \color{#FF6800}{ 203 } } { \color{#FF6800}{ 20 } } } - 8 \dfrac { 7 } { 25 }$

$\dfrac { 203 } { 20 } \color{#FF6800}{ - } \color{#FF6800}{ 8 \dfrac { \color{#FF6800}{ 7 } } { \color{#FF6800}{ 25 } } }$

$ $ Convert mixed number into improper fraction $ $

$\dfrac { 203 } { 20 } \color{#FF6800}{ - } \color{#FF6800}{ \dfrac { \color{#FF6800}{ 207 } } { \color{#FF6800}{ 25 } } }$

$\dfrac { 203 } { \color{#FF6800}{ 20 } } - \dfrac { 207 } { \color{#FF6800}{ 25 } }$

$ $ The smallest common multiple in denominator is $ 100$

$\dfrac { 203 } { \color{#FF6800}{ 20 } } - \dfrac { 207 } { \color{#FF6800}{ 25 } }$

$\dfrac { 203 } { 20 } - \dfrac { 207 } { 25 }$

$ $ Multiply the denominator and the numerator so that the denominator is the smallest common multiple $ $

$\dfrac { 203 \times \color{#FF6800}{ 5 } } { 20 \times \color{#FF6800}{ 5 } } - \dfrac { 207 \times \color{#FF6800}{ 4 } } { 25 \times \color{#FF6800}{ 4 } }$

$\color{#FF6800}{ \dfrac { \color{#FF6800}{ 203 } \color{#FF6800}{ \times } \color{#FF6800}{ 5 } } { \color{#FF6800}{ 20 } \color{#FF6800}{ \times } \color{#FF6800}{ 5 } } } \color{#FF6800}{ - } \color{#FF6800}{ \dfrac { \color{#FF6800}{ 207 } \color{#FF6800}{ \times } \color{#FF6800}{ 4 } } { \color{#FF6800}{ 25 } \color{#FF6800}{ \times } \color{#FF6800}{ 4 } } }$

$ $ Organize the expression $ $

$\color{#FF6800}{ \dfrac { \color{#FF6800}{ 1015 } } { \color{#FF6800}{ 100 } } } \color{#FF6800}{ - } \color{#FF6800}{ \dfrac { \color{#FF6800}{ 828 } } { \color{#FF6800}{ 100 } } }$

$\color{#FF6800}{ \dfrac { \color{#FF6800}{ 1015 } } { \color{#FF6800}{ 100 } } } \color{#FF6800}{ - } \color{#FF6800}{ \dfrac { \color{#FF6800}{ 828 } } { \color{#FF6800}{ 100 } } }$

$ $ Since the denominator is the same as $ 100 $ , combine the fractions into one $ $

$\color{#FF6800}{ \dfrac { \color{#FF6800}{ 1015 } \color{#FF6800}{ - } \color{#FF6800}{ 828 } } { \color{#FF6800}{ 100 } } }$

$\dfrac { \color{#FF6800}{ 1015 } \color{#FF6800}{ - } \color{#FF6800}{ 828 } } { 100 }$

$ $ Subtract $ 828 $ from $ 1015$

$\dfrac { \color{#FF6800}{ 187 } } { 100 }$

Solution search results

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In the following problem $a,b,$ b,and c represent REAL NUMBERS. The derivative of $g\left(x\right)=log _{a}\left(bx\right)+cx^{2}is$ $○$ $g^{1}\left(x\right)=\right)dfrac\left(b\right)log _{-}a\left(bx\right)\right)\left(N1n$ $a\right)+2cx1\right)$ $○$ $\left(g\left(x\right)=\right)dtracb$ $loga\left(bx\right)+2c\times \right)Nln$ a}\) $○$ $g^{'}\left(x\right)=\left(dfraC\left(a\right)log _{-}a\left(bx\right)\right)\left(ln$ $\right)+2c\times 1\right)\right)$ $○$ $g^{1}\left(x\right)=\left(dfrac\left(b$ $log _{-}a\left(bx\right)\right)\left(ln$ $a1\right)$ $○$ $\left(\left(g^{1}\left(x\right)=b$ $log _{-}a\left(bx\right)+2cx1\right)$ $○$ $g\left(x\right)=\left(dfrac\left(b$ $log _{-}a\left(bx\right)\right)\left(1ln$ $a|+2c1\right)$

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$\left(\left(72\div 9\right)\times 6-20\right)-8$

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