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Solve the equation
Answer
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$y = 1 - 2 x$
$y = - \left ( x - 5 \right )$
$x$Intercept
$\left ( \dfrac { 1 } { 2 } , 0 \right )$
$y$Intercept
$\left ( 0 , 1 \right )$
$x$Intercept
$\left ( 5 , 0 \right )$
$y$Intercept
$\left ( 0 , 5 \right )$
$1-2x = - \left( x-5 \right)$
$x = - 4$
$ $ Solve a solution to $ x$
$1 - 2 x = \color{#FF6800}{ - } \left ( \color{#FF6800}{ x } \color{#FF6800}{ - } \color{#FF6800}{ 5 } \right )$
$ $ Change the symbol of each term in parentheses when there is a (-) symbol in front of parentheses $ $
$1 - 2 x = \color{#FF6800}{ - } \color{#FF6800}{ x } \color{#FF6800}{ + } \color{#FF6800}{ 5 }$
$\color{#FF6800}{ 1 } \color{#FF6800}{ - } \color{#FF6800}{ 2 } \color{#FF6800}{ x } = - x + 5$
$ $ Organize the expression $ $
$\color{#FF6800}{ - } \color{#FF6800}{ 2 } \color{#FF6800}{ x } \color{#FF6800}{ + } \color{#FF6800}{ 1 } = - x + 5$
$- 2 x + 1 = \color{#FF6800}{ - } \color{#FF6800}{ x } + 5$
$ $ Move the variable to the left-hand side and change the symbol $ $
$- 2 x + 1 \color{#FF6800}{ + } \color{#FF6800}{ x } = 5$
$- 2 x \color{#FF6800}{ + } \color{#FF6800}{ 1 } + x = 5$
$ $ Move the constant to the right side and change the sign $ $
$- 2 x + x = 5 \color{#FF6800}{ - } \color{#FF6800}{ 1 }$
$\color{#FF6800}{ - } \color{#FF6800}{ 2 } \color{#FF6800}{ x } \color{#FF6800}{ + } \color{#FF6800}{ x } = 5 - 1$
$ $ Organize the expression $ $
$\color{#FF6800}{ - } \color{#FF6800}{ x } = 5 - 1$
$- x = \color{#FF6800}{ 5 } \color{#FF6800}{ - } \color{#FF6800}{ 1 }$
$ $ Subtract $ 1 $ from $ 5$
$- x = \color{#FF6800}{ 4 }$
$\color{#FF6800}{ - } \color{#FF6800}{ x } = \color{#FF6800}{ 4 }$
$ $ Change the sign of both sides of the equation $ $
$\color{#FF6800}{ x } = \color{#FF6800}{ - } \color{#FF6800}{ 4 }$
$ $ 그래프 보기 $ $
Graph
Solution search results
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numbers is $45$ and one number is $X$ 
.This statement in the form of 
equation $1s:$ 
$\left(1$ Point) $\right)$ 
$○5x+1$ $1eft\left(x+1$ $r1gnt\right)=45s$ 
$○sx+1ef\left(x+2$ $r1gnt\right)=145s$ 
$sx+1x=45s$
7th-9th grade
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search-thumbnail-$s|ef\left(-1n$ $\left($ }\right)^{50}\ $\right)$ \ | | is\ equal\ to\ $S$ 
$s1S$ 
$S-1S$ 
$s2S$ 
$s50s$
7th-9th grade
Other
search-thumbnail-Given the set of ordered pairs $\left(\left(-7.0\right),\left(-6,5\right),\left(-5,-3\right),\left(-1,2\right)$ $\left(1,6\right),\left(2,-2\right)$ $\left(5,3\right)\left(7,-8\right)\right)$ 
Find f(7)fAleft(7\right) 
O a 
O b -8 
6. 
$5$
7th-9th grade
Algebra
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