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Solve the equation
Answer
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$1- \dfrac{ -1-a }{ 2 } = \dfrac{ -1+3a }{ 4 }$
$a = 7$
$ $ Solve a solution to $ a$
$1 - \dfrac { \color{#FF6800}{ - } \color{#FF6800}{ 1 } \color{#FF6800}{ - } \color{#FF6800}{ a } } { 2 } = \dfrac { - 1 + 3 a } { 4 }$
$ $ Organize the expression $ $
$1 - \dfrac { \color{#FF6800}{ - } \color{#FF6800}{ a } \color{#FF6800}{ - } \color{#FF6800}{ 1 } } { 2 } = \dfrac { - 1 + 3 a } { 4 }$
$1 - \dfrac { - a - 1 } { 2 } = \dfrac { \color{#FF6800}{ - } \color{#FF6800}{ 1 } \color{#FF6800}{ + } \color{#FF6800}{ 3 } \color{#FF6800}{ a } } { 4 }$
$ $ Organize the expression $ $
$1 - \dfrac { - a - 1 } { 2 } = \dfrac { \color{#FF6800}{ 3 } \color{#FF6800}{ a } \color{#FF6800}{ - } \color{#FF6800}{ 1 } } { 4 }$
$\color{#FF6800}{ 1 } \color{#FF6800}{ - } \color{#FF6800}{ \dfrac { - a - 1 } { 2 } } = \color{#FF6800}{ \dfrac { 3 a - 1 } { 4 } }$
$ $ Multiply both sides by the least common multiple for the denominators to eliminate the fraction $ $
$\color{#FF6800}{ 4 } \color{#FF6800}{ - } \left ( \color{#FF6800}{ 2 } \left ( \color{#FF6800}{ - } \color{#FF6800}{ a } \color{#FF6800}{ - } \color{#FF6800}{ 1 } \right ) \right ) = \color{#FF6800}{ 3 } \color{#FF6800}{ a } \color{#FF6800}{ - } \color{#FF6800}{ 1 }$
$\color{#FF6800}{ 4 } \color{#FF6800}{ - } \left ( \color{#FF6800}{ 2 } \left ( \color{#FF6800}{ - } \color{#FF6800}{ a } \color{#FF6800}{ - } \color{#FF6800}{ 1 } \right ) \right ) = \color{#FF6800}{ 3 } \color{#FF6800}{ a } \color{#FF6800}{ - } \color{#FF6800}{ 1 }$
$ $ Organize the expression $ $
$\color{#FF6800}{ 2 } \color{#FF6800}{ a } \color{#FF6800}{ - } \color{#FF6800}{ 3 } \color{#FF6800}{ a } = \color{#FF6800}{ - } \color{#FF6800}{ 1 } \color{#FF6800}{ - } \color{#FF6800}{ 6 }$
$\color{#FF6800}{ 2 } \color{#FF6800}{ a } \color{#FF6800}{ - } \color{#FF6800}{ 3 } \color{#FF6800}{ a } = - 1 - 6$
$ $ Organize the expression $ $
$\color{#FF6800}{ - } \color{#FF6800}{ a } = - 1 - 6$
$- a = \color{#FF6800}{ - } \color{#FF6800}{ 1 } \color{#FF6800}{ - } \color{#FF6800}{ 6 }$
$ $ Find the sum of the negative numbers $ $
$- a = \color{#FF6800}{ - } \color{#FF6800}{ 7 }$
$\color{#FF6800}{ - } \color{#FF6800}{ a } = \color{#FF6800}{ - } \color{#FF6800}{ 7 }$
$ $ Change the sign of both sides of the equation $ $
$\color{#FF6800}{ a } = \color{#FF6800}{ - } \left ( \color{#FF6800}{ - } \color{#FF6800}{ 7 } \right )$
$a = \color{#FF6800}{ - } \left ( \color{#FF6800}{ - } 7 \right )$
$ $ Simplify Minus $ $
$a = 7$
Solution search results
search-thumbnail-$x=\dfrac {4x+1} {5}-\dfrac {0-a} {4}$ 
$1$ $-$
7th-9th grade
Calculus
search-thumbnail-$2$ Hasil dari $\dfrac {a+1} {4}-\dfrac {a-1} {3}$ adalah.. 
$a$ $\dfrac {a+7} {12}$ C. $\dfrac {7-a} {12}$ 
b. $\dfrac {a-1} {12}$ d. $\dfrac {-1-a} {12}$
10th-13th grade
Algebra
search-thumbnail-Which of the following rational numbers are 
equivalent? 
$0Ptionsy$ 
A \frac{5}{6}, \frac{30}{36} 
B $s\sqrt{rac\left(} -2\right)\left(3\right)\sqrt{1rac} \sqrt{4\right)16\right)4} $ 
C $s\sqrt{11aC\left(} -4\right)1-7b,\sqrt{1rac\left(16\sqrt{35\right)9} } $ 
D \frac{1}{2},\frac{3}{8}
7th-9th grade
Other
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