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Formula
Calculate the value
Answer
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Find the approximate value
Answer
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Square root
Answer
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$1 \times \sqrt{ 5 }$
$\sqrt{ 5 }$
Calculate the value
$\color{#FF6800}{ 1 } \sqrt{ 5 }$
$ $ Multiplying any number by 1 does not change the value $ $
$\sqrt{ 5 }$
$\approx 2.2361$
Find the approximate value
$\color{#FF6800}{ 1 } \sqrt{ \color{#FF6800}{ 5 } }$
$ $ Find the approximate value of the square root $ $
$\approx \color{#FF6800}{ 2.2361 }$
$\sqrt{ 5 }$
Change the expression
$\color{#FF6800}{ 1 } \sqrt{ \color{#FF6800}{ 5 } }$
$ $ Put the coefficient into the square root $ $
$\sqrt{ \color{#FF6800}{ 1 } ^ { \color{#FF6800}{ 2 } } \color{#FF6800}{ \times } \color{#FF6800}{ 5 } }$
$\sqrt{ \color{#FF6800}{ 1 } ^ { \color{#FF6800}{ 2 } } \color{#FF6800}{ \times } \color{#FF6800}{ 5 } }$
$ $ Simplify the expression $ $
$\sqrt{ \color{#FF6800}{ 1 } \color{#FF6800}{ \times } \color{#FF6800}{ 5 } }$
$\sqrt{ \color{#FF6800}{ 1 } \times 5 }$
$ $ Multiplying any number by 1 does not change the value $ $
$\sqrt{ \color{#FF6800}{ 5 } }$
Solution search results
search-thumbnail-$4$ Find the missing lengths. 
$b$ 
$45^{°}$ 
$2\sqrt{2} $ 
$F$ $a=2$ and $b=2+sq\pi \left(2\right)$ 
$6$ $a=sq\pi \left(2\right)$ and $b=2\times sq\pi \left(2\right)$ 
$I$ 
$H$ $a$ $=2\times sq\pi \left(2\right)$ and $b=2\times sq\pi \left(2\right)$ 
$3$ a $=4$ and $b=2+sq\pi \left(2\right)$
10th-13th grade
Other
search-thumbnail-$x$ 
$45^{°}$ 
$6$ 
Find $x$ 
$O6$ 
$\square 6sq\pi \left(2\right)$ 
sqrt $\left(2\right)$ 
$○12sq$ 
$○3s$ sqrt $\left(2\right)$
10th-13th grade
Calculus
search-thumbnail-The rationalizing factor of \sqrt{23} is 
$°$ $Options^{°}$ $0$ 
A 24 
23 
C \sqrt{23} 
D None of these
7th-9th grade
Other
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