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Formula
Solve the equation
Answer
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Graph
$x = 0.2 \left ( y - 3 \right )$
$x = 0.6 y - 1$
$x$-intercept
$\left ( - \dfrac { 3 } { 5 } , 0 \right )$
$y$-intercept
$\left ( 0 , 3 \right )$
$x$-intercept
$\left ( - 1 , 0 \right )$
$y$-intercept
$\left ( 0 , \dfrac { 5 } { 3 } \right )$
$0.2 \left( y-3 \right) = 0.6y-1$
$y = 1$
$ $ Solve a solution to $ y$
$\color{#FF6800}{ 0.2 } \left ( \color{#FF6800}{ y } \color{#FF6800}{ - } \color{#FF6800}{ 3 } \right ) = 0.6 y - 1$
$ $ Multiply each term in parentheses by $ 0.2$
$\color{#FF6800}{ 0.2 } \color{#FF6800}{ y } \color{#FF6800}{ + } \color{#FF6800}{ 0.2 } \color{#FF6800}{ \times } \left ( \color{#FF6800}{ - } \color{#FF6800}{ 3 } \right ) = 0.6 y - 1$
$\color{#FF6800}{ 0.2 } \color{#FF6800}{ y } + 0.2 \times \left ( - 3 \right ) = 0.6 y - 1$
$ $ Calculate the multiplication expression $ $
$\color{#FF6800}{ \dfrac { y } { 5 } } + 0.2 \times \left ( - 3 \right ) = 0.6 y - 1$
$\dfrac { y } { 5 } + \color{#FF6800}{ 0.2 } \color{#FF6800}{ \times } \left ( \color{#FF6800}{ - } \color{#FF6800}{ 3 } \right ) = 0.6 y - 1$
$ $ Multiply $ 0.2 $ and $ - 3$
$\dfrac { y } { 5 } \color{#FF6800}{ - } \color{#FF6800}{ 0.6 } = 0.6 y - 1$
$\dfrac { y } { 5 } \color{#FF6800}{ - } \color{#FF6800}{ 0.6 } = 0.6 y - 1$
$ $ Convert decimals to fractions $ $
$\dfrac { y } { 5 } \color{#FF6800}{ - } \color{#FF6800}{ \dfrac { 3 } { 5 } } = 0.6 y - 1$
$\dfrac { y } { 5 } - \dfrac { 3 } { 5 } = \color{#FF6800}{ 0.6 } \color{#FF6800}{ y } - 1$
$ $ Calculate the multiplication expression $ $
$\dfrac { y } { 5 } - \dfrac { 3 } { 5 } = \color{#FF6800}{ \dfrac { 3 y } { 5 } } - 1$
$\color{#FF6800}{ \dfrac { y } { 5 } } \color{#FF6800}{ - } \color{#FF6800}{ \dfrac { 3 } { 5 } } = \color{#FF6800}{ \dfrac { 3 y } { 5 } } \color{#FF6800}{ - } \color{#FF6800}{ 1 }$
$ $ Multiply both sides by the least common multiple for the denominators to eliminate the fraction $ $
$\color{#FF6800}{ y } \color{#FF6800}{ - } \color{#FF6800}{ 3 } = \color{#FF6800}{ 3 } \color{#FF6800}{ y } \color{#FF6800}{ - } \color{#FF6800}{ 5 }$
$\color{#FF6800}{ y } \color{#FF6800}{ - } \color{#FF6800}{ 3 } = \color{#FF6800}{ 3 } \color{#FF6800}{ y } \color{#FF6800}{ - } \color{#FF6800}{ 5 }$
$ $ Organize the expression $ $
$\color{#FF6800}{ y } \color{#FF6800}{ - } \color{#FF6800}{ 3 } \color{#FF6800}{ y } = \color{#FF6800}{ - } \color{#FF6800}{ 5 } \color{#FF6800}{ + } \color{#FF6800}{ 3 }$
$\color{#FF6800}{ y } \color{#FF6800}{ - } \color{#FF6800}{ 3 } \color{#FF6800}{ y } = - 5 + 3$
$ $ Organize the expression $ $
$\color{#FF6800}{ - } \color{#FF6800}{ 2 } \color{#FF6800}{ y } = - 5 + 3$
$\color{#FF6800}{ - } \color{#FF6800}{ 2 } \color{#FF6800}{ y } = \color{#FF6800}{ - } \color{#FF6800}{ 5 } \color{#FF6800}{ + } \color{#FF6800}{ 3 }$
$ $ Organize the expression $ $
$\color{#FF6800}{ 2 } \color{#FF6800}{ y } = \color{#FF6800}{ 2 }$
$\color{#FF6800}{ 2 } \color{#FF6800}{ y } = \color{#FF6800}{ 2 }$
$ $ Divide both sides by the same number $ $
$\color{#FF6800}{ y } = \color{#FF6800}{ 1 }$
$ $ 그래프 보기 $ $
Graph
Solution search results
search-thumbnail-If the sum of two consecutive 
numbers is $45$ and one number is $X$ 
.This statement in the form of 
equation $1s:$ 
$\left(1$ Point) $\right)$ 
$○5x+1$ $1eft\left(x+1$ $r1gnt\right)=45s$ 
$○sx+1ef\left(x+2$ $r1gnt\right)=145s$ 
$sx+1x=45s$
7th-9th grade
Algebra
search-thumbnail-$s|ef\left(-1n$ $\left($ }\right)^{50}\ $\right)$ \ | | is\ equal\ to\ $S$ 
$s1S$ 
$S-1S$ 
$s2S$ 
$s50s$
7th-9th grade
Other
search-thumbnail-Given the set of ordered pairs $\left(\left(-7.0\right),\left(-6,5\right),\left(-5,-3\right),\left(-1,2\right)$ $\left(1,6\right),\left(2,-2\right)$ $\left(5,3\right)\left(7,-8\right)\right)$ 
Find f(7)fAleft(7\right) 
O a 
O b -8 
6. 
$5$
7th-9th grade
Algebra
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