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Convert decimals to fractions

Answer

$\dfrac { 64 } { 495 }$

Convert the repeating decimal number to a fraction

$\color{#FF6800}{ 0.1 \dot{ 2 } \dot{ 9 } }$

$ $ Set the repeating decimal number to x $ $

$\color{#FF6800}{ x } = \color{#FF6800}{ 0.1 \dot{ 2 } \dot{ 9 } }$

$ $ Multiply both sides by an appropriate power of 10 to make two expressions with the same part of the prime number $ $

$\begin{cases} \color{#FF6800}{ 1000 } \color{#FF6800}{ x } = \color{#FF6800}{ 129. \dot{ 2 } \dot{ 9 } } \\ \color{#FF6800}{ 10 } \color{#FF6800}{ x } = \color{#FF6800}{ 1. \dot{ 2 } \dot{ 9 } } \end{cases}$

$ $ Since the prime number part of the right side of the two expressions is the same, only the integer part remains $ $

$\color{#FF6800}{ 990 } \color{#FF6800}{ x } = \color{#FF6800}{ 128 }$

$ $ Divide both sides by the same number $ $

$\color{#FF6800}{ x } = \color{#FF6800}{ \dfrac { \color{#FF6800}{ 64 } } { \color{#FF6800}{ 495 } } }$

Solution search results

$1$ $x$ $1$ $\left(xx\right)$ u $1$ a a a $1tn∈$ $7$ then prove that] $\left(1\right)$ $sin\left(\left(2n+1\right)\pi +θ\right)=\left(-1\right)^{2n+1}$ $sinθ$ $11\right)$ $tan\left(n\pi +θ\right)=cot\left(2n+1\right)\dfrac {\pi } {2}-θ\right)$

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