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Formula
Find the sum
Answer
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$-9-4$
$- 13$
Find the sum of the negative numbers
$\color{#FF6800}{ - } 9 \color{#FF6800}{ - } 4$
$ $ Put negative numbers in parentheses $ $
$\color{#FF6800}{ - } \left ( 9 + 4 \right )$
$- \left ( \color{#FF6800}{ 9 } \color{#FF6800}{ + } \color{#FF6800}{ 4 } \right )$
$ $ Add $ 9 $ and $ 4$
$- \color{#FF6800}{ 13 }$
Solution search results
search-thumbnail-$°$ $-$ $12$ 
$y=x$ 
-2 - 23 
$x-3$ $\left(y^{|}9$ $-$ $9|4$ $1|0|1|4|9$ 
$2.$ $y=2x^{2}$ 
*-3 -2 e - 161 $|2|3$ 

6 188 8 18
3. $y=\dfrac {1} {2}x^{2}$ 

$x-3-2|-1$ $0$ 0 $2|3$ 
$y$ $4.5$ $2$ $0.5$ $0$ $0.52$ $4.5$ 

$y=\sqrt{-x^{8}} $ 
$4.y$ 
$1$ $23$ $|^{x-3-2-10}$ $y-9$ $-4-1-0-1-4-9$ 
$5.y=\dfrac {1} {2}x^{2}$ 
$x-3-2-1$ $0$ $1|2|3$ 
$y-45-2-o50-05-2$ -45
7th-9th grade
Algebra
search-thumbnail-Draw the graph for the equation $y=-$ $x^{2}+3$ for values of x $trom-3$ to 3, 
1. the table of values is given below. (3 Marks) 
$-3$ $-2$ $-1$ 1 2. 3. 
$-x^{2}$ $-9$ $-4$ - 1 $-1$ $-4$ $-9$ 
$+3$ 3. 3. 3 3 3 3 3 
$Y=-x^{2}+3$ $-6$ $-1$ 2 3 2. $-1$ $-6$ 
(1 mark) 

5. 
4 
3. 
2. 

5 . 42 3, 4 
"2 
"3 
-4 
5 
9. 
7 
"8
10th-13th grade
Other
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