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Find the sum
Answer
$- 14$
Find the sum of the negative numbers
$\color{#FF6800}{ - } 6 \color{#FF6800}{ - } 8$
$ $ Put negative numbers in parentheses $ $
$\color{#FF6800}{ - } \left ( 6 + 8 \right )$
$- \left ( \color{#FF6800}{ 6 } \color{#FF6800}{ + } \color{#FF6800}{ 8 } \right )$
$ $ Add $ 6 $ and $ 8$
$- \color{#FF6800}{ 14 }$
Solution search results
![search-thumbnail-21-(2x-(8+21-(6-8)3 ]](https://thumb-m.mathpresso.io/qanda-thumbnail-storage/questions/eQKU7nfRyTQaUkqTwYhovUqEhM7s4ZCJRFkBuGphEFe0Tdnf5pCpx.jpg?target_format=webp&width=652)
$1$
$21-\left(2x-\left(8+21-\left(6-8\right)3$ ]
1st-6th grade
Algebra
$10-04.\bar{6-8} \times 3\right).\left(2$ $2-10$
7th-9th grade
Other
$∩000$
$8=y.50$ $A0=6.7$ $7$ $2=50$
10th-13th grade
Other
$8$
$6$
$4$
$2$
$-8$ $26$ $-a$ $-2$ $2$ $4$ $6$ $8$
$-2$
$.4$
$-6$
$-8$
$1$
10th-13th grade
Algebra
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