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Solve the inequality
Answer
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Graph
$- 3 x < 15$
$- 3 x < 15$
Solution of inequality
$x > - 5$
$x > - 5$
$ $ Solve a solution to $ x$
$\color{#FF6800}{ - } \color{#FF6800}{ 3 } \color{#FF6800}{ x } < \color{#FF6800}{ 15 }$
$ $ Change the symbol of the inequality of both sides, and reverse the symbol of the inequality to the opposite direction $ $
$3 x > - 15$
$\color{#FF6800}{ 3 } \color{#FF6800}{ x } > \color{#FF6800}{ - } \color{#FF6800}{ 15 }$
$ $ Divide both sides by the same number $ $
$\color{#FF6800}{ x } > \color{#FF6800}{ - } \color{#FF6800}{ 5 }$
Solution search results
search-thumbnail-2 f(x)=\begin{cases}2x+1\\x\geq1\\\dfrac{1}{2}x-3x<1\end{cases}
$2$ $f\left(x\right)= \begin{cases} 2x+1 \\ x\geq 1 \\ \dfrac {1} {2}x-3x<1 \end{cases} $ Function? $ye5OrNO$ $f\left(-2\right)=$ $f\left(6\right)=$ $f\left(1\right)=$
10th-13th grade
Calculus
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search-thumbnail-4. f(x)=\begin{cases}x+3\\3-x\end{cases} x∈2
$3.$ $3$ $x=0$ $x\geq 2$ $4.$ $f\left(x\right)= \begin{cases} x+3 \\ 3-x \end{cases} $ $x∈2$ $6$ $x\leq 1$ $f\left(x\right)= \begin{cases} 2x+3 \\ 5 \\ 3x+2 \end{cases} $ $x>1$ $x=1$
10th-13th grade
Other
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search-thumbnail-(a) Solve the following AN AND graph the solution on a number line. (3marks)
Question $1$ $\left(a\right)$ Solve the following $AN$ AND graph the solution on a number line. $\left(3marks\right)$ $-3x\leq 12$
Other
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search-thumbnail-f(x)=\begin{cases}x+3\\3-x\end{cases}
$4$ $x\geq 2$ $f\left(x\right)= \begin{cases} x+3 \\ 3-x \end{cases} $ $x\leq 2$ $6.$ $x\leq 1$ $f\left(x\right)= \begin{cases} 2x+3 \\ 5 \\ 3x+2 \end{cases} $ $x=1$ $x>1$ $8.$ $x≠0$ $\dfrac {1anx} {x}$ $f\left(x\right)=\left($ $1$ $x=0$ $10.$ $f\left(x\right)=\int $ $\dfrac {sinx} {3x}$ $x$ $x$ 0
10th-13th grade
Other
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search-thumbnail-Which of the following is the solution statement for
$+19$ Which of the following is the solution statement for the inequality shown below? $-5<1-$ $3x<10$ F. G. $-5<x<1$ $-3<x$ $-3<x<2$ H. J. $-2<$ $x<3$ K. $x<-30rx>2$
Algebra
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