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Solve the equation
Answer
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Graph
$y = - 3.2$
$y = - \dfrac { 4 } { 7 } x - 4$
$x$Intercept
$\left ( - 7 , 0 \right )$
$y$Intercept
$\left ( 0 , - 4 \right )$
$-3.2 = - \dfrac{ 4 }{ 7 } x-4$
$x = - \dfrac { 7 } { 5 }$
$ $ Solve a solution to $ x$
$\color{#FF6800}{ - } \color{#FF6800}{ 3.2 } = - \dfrac { 4 } { 7 } x - 4$
$ $ Convert decimals to fractions $ $
$\color{#FF6800}{ - } \color{#FF6800}{ \dfrac { 16 } { 5 } } = - \dfrac { 4 } { 7 } x - 4$
$- \dfrac { 16 } { 5 } = \color{#FF6800}{ - } \color{#FF6800}{ \dfrac { 4 } { 7 } } \color{#FF6800}{ x } - 4$
$ $ Calculate the multiplication expression $ $
$- \dfrac { 16 } { 5 } = \color{#FF6800}{ - } \color{#FF6800}{ \dfrac { 4 x } { 7 } } - 4$
$\color{#FF6800}{ - } \color{#FF6800}{ \dfrac { 16 } { 5 } } = \color{#FF6800}{ - } \color{#FF6800}{ \dfrac { 4 x } { 7 } } \color{#FF6800}{ - } \color{#FF6800}{ 4 }$
$ $ Multiply both sides by the least common multiple for the denominators to eliminate the fraction $ $
$\color{#FF6800}{ - } \color{#FF6800}{ \dfrac { 112 } { 5 } } = \color{#FF6800}{ - } \color{#FF6800}{ 4 } \color{#FF6800}{ x } \color{#FF6800}{ - } \color{#FF6800}{ 28 }$
$- \dfrac { 112 } { 5 } = \color{#FF6800}{ - } \color{#FF6800}{ 4 } \color{#FF6800}{ x } - 28$
$ $ Move the variable to the left-hand side and change the symbol $ $
$- \dfrac { 112 } { 5 } \color{#FF6800}{ + } \color{#FF6800}{ 4 } \color{#FF6800}{ x } = - 28$
$\color{#FF6800}{ - } \color{#FF6800}{ \dfrac { 112 } { 5 } } + 4 x = - 28$
$ $ Move the constant to the right side and change the sign $ $
$4 x = - 28 \color{#FF6800}{ + } \color{#FF6800}{ \dfrac { 112 } { 5 } }$
$4 x = \color{#FF6800}{ - } \color{#FF6800}{ 28 } \color{#FF6800}{ + } \color{#FF6800}{ \dfrac { 112 } { 5 } }$
$ $ Get the subtract $ $
$4 x = \color{#FF6800}{ - } \color{#FF6800}{ \dfrac { 28 } { 5 } }$
$\color{#FF6800}{ 4 } \color{#FF6800}{ x } = \color{#FF6800}{ - } \color{#FF6800}{ \dfrac { 28 } { 5 } }$
$ $ Divide both sides by the same number $ $
$\color{#FF6800}{ x } = \color{#FF6800}{ - } \color{#FF6800}{ \dfrac { 7 } { 5 } }$
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