Solve the system of equations 2x-y=1; x+2y=8 graphically and find the coordinates of the points where corresponding lines intersect y-axis.
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Calculate the sum or the difference
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$- 1$
Calculate the sum or the difference
$\color{#FF6800}{ - } \color{#FF6800}{ 2 } + 3 + 5 \color{#FF6800}{ - } \color{#FF6800}{ 7 }$
$ $ Find the sum of the negative numbers $ $
$\color{#FF6800}{ - } \color{#FF6800}{ 9 } + 3 + 5$
$- 9 + \color{#FF6800}{ 3 } \color{#FF6800}{ + } \color{#FF6800}{ 5 }$
$ $ Add $ 3 $ and $ 5$
$- 9 + \color{#FF6800}{ 8 }$
$\color{#FF6800}{ - } \color{#FF6800}{ 9 } \color{#FF6800}{ + } \color{#FF6800}{ 8 }$
$ $ Add $ - 9 $ and $ 8$
$\color{#FF6800}{ - } \color{#FF6800}{ 1 }$
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Observe the following pattern and complete. $=1$ $1+3$ $=4=2^{2}$ $1+3+5=9=3^{2}$ $1+3+5+7=16=4$ ou agree $1=1=1^{2}$ $1+3=4=2^{2}$ $1+3+5=9=3^{2}$ $1+3+5+7=16=4^{2}$ $1+3+5+7+9=25=5^{2}$ $1+3+5+7+9+11=$ $=\left(\right)^{2}$ $1+3+5+7+9+11+13=$ .. $=\left(\right)^{2}$
Probability and Statistics
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Observe the following pattern and complete. $1=1^{2}$ $1+3=4=2^{2}$ $1+3+5=9=3^{2}$ $+3\div 5+7-16=4$ $1=1=1^{2}$ $1+3=4=2^{2}$ $1+3+5=9=3^{2}$ $1+3+5+7=16=4^{2}$ $1+3+5+7+9=25=5^{2}$ $1+3+5+7+9+11=$ =. $=\left(\right)^{2}$ $3=..........$ $=\left(\right)^{2}$ $1+3+5+7+9+11+13=$ N this, we can generalize that the sum of first 'n' odd natural numbers is equal to 'n".
English
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$2$ , Interesting patterns in square: Observe the following pattern and complete. $1=1$ $1+3=4=2^{2}$ $1+3+5=9=3^{2}$ $+3+5+7=16=4$ ou agree $1=1=1^{2}$ $1+3=4=2^{2}$ $1+3+5=9=3^{2}$ $1+3+5+7=16=4^{2}$ $1+3+5+7+9=25=5^{2}$ $1+3+5+7+9+11=$ $=\left(\right)^{2}$ $1+3+5+7+9+11+13=$ $=\left(\right)^{2}$ n this, we can generalize that the sum of first 'n'odd natural numbers is equal to 'n".
7th-9th grade
Algebra
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10th-13th grade
Other
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$2+3+5-8-3+10$
10th-13th grade
Other
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$2+3+5=7$
10th-13th grade
Other
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