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Formula
Find the sum
Answer
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$-14-9$
$- 23$
Find the sum of the negative numbers
$\color{#FF6800}{ - } 14 \color{#FF6800}{ - } 9$
$ $ Put negative numbers in parentheses $ $
$\color{#FF6800}{ - } \left ( 14 + 9 \right )$
$- \left ( \color{#FF6800}{ 14 } \color{#FF6800}{ + } \color{#FF6800}{ 9 } \right )$
$ $ Add $ 14 $ and $ 9$
$- \color{#FF6800}{ 23 }$
Solution search results
search-thumbnail-Comparing Integers $\left(A\right)$ 
$lnstn1ctions:$ Compare the pairs of integers using $<,>$ $or=$ 
-6 -7 -8 12 10 -10 
13 11 -1 13 -14 1 -5 
4 $\bar{\square } $ -14 -11 $-$ -7 $\bar{\square } $ -1 -8 1 
-4 -1 -2 $\bar{\square } -7$ 11 $-14$ 14 
10 -13 14 -9 $-15^{-}$ 7 8 $-$ -2
1st-6th grade
Other
search-thumbnail-Comparing Integers $\left(A\right)$ 
$lnstn1ctions:$ Compare the pairs of integers using $<,>,or=$ 
-6 -7 -8 $-2$ 12 10 $-10$ 
13 11 -1 13 -14 1 $-5\square $ 9. 
4 $-$ $-14$ $-11\square $ -7 $-$ -1 $-8\bar{\square } $ 1 
-4 $-$ -1 -2 $-$ -7 $-$ 11 -14 14 
10 $-13$ 14 $-$ -9 -15 7 8 $-$ -2
1st-6th grade
Other
search-thumbnail-What is the product? 
$3°$ $-6$ $-11$ 
$-14$ $-9$ 
$ \begin{cases} -3 \\ -11 \end{cases} $ $-8$ 
$0$ $-6$ 
$-18$ 
$|^{-18}$ $-42$ $-33\right)$ $-27$ 
$\square $ $18$ $42$ $33\right)$ $27$ 
$\square $ $3$ $11$ $8$ 
$B$
10th-13th grade
Calculus
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