Calculate the value

The is the statement of the Mean Value Theorem from your $te\times tb00k$ 
$Tneoren$ $m4.5$ $Ne8n$ Value Theorem 
Let f be continuous over $leclose$ interval $\left(a.b\right)aod$ $i$ $eo$ $xd$ $csnlc$ $\left(ab\right)$ $mmd$ 
exists at least one point cE $\left(a.b\right)$ $si1dhtba$ 
$f^{'}\left(c\right)=\dfrac {f\left(b\right)-f\left(a\right)} {b-a}$ 
What is the geometric interpretation of the conclusion of the theorem? 
O The tangent line to the graph of $f\left(x\right)$ at $l\left(c1\right)$ is parallel to the 
secant line connecting $\left(a,f\left(a\right)\right)$ and 
$\left(b,f\left(b\right)\right)$. 
O The tangent line to the graph of $\left(f\left(lef\left(x\left(right\right)$ at $c$ is the secant line 
connecting $\left(a,f\left(a\right)\right)$ $ana$ $\left(b,f\left(b\right)\right)$. 
O The tangent line to the graph $of$ $\left(f\left(leF\left(x\left(right\right)\left(\right)at1\left(c1\right)is$ perpendicular to the 
secant line connecting $\left(a,f\left(a\right)\right)$ and 
A(\left(b,f\left(b\right)\right)\). 
O The tangent line to the graph of $\left(fleH\left(x\right)nght\right)\right)\right)$ $at$ $\left(c\right)\right)ishoizonta|$ 
$Tnere$ is more than one tangent line to the graph $0no$ $\left(flcf\left(x\right)night\right)\left($ $at1\left(c1\right)$ 

What is the inverse of $g\left(x\right)=\sqrt{x-1} $ 
$Og\left(x\right)=\sqrt{x+1} $ 
$+1$ $g^{'}\left(x\right)=5-$ $y_{9}$ $g\sqrt{ef\left(x\left(nght\right)} =\left(f_{tac\left(x+1\right)0sq\pi \left(x\right)}$ 
$Og^{'}\left(x\right)=x^{2}+1$ 
$○g\left(x\right)=x^{2}-1$ 
« Previous Ne 

$11.$ Question $11$ 
Solve the $:$ $folloMlng'$ $0<θ<90^{°}$ 
$\left(1\right)$ $2sin^{2}θ=1\right)$ $\left(rac\left(3\right)\left(2\right)\right)$ 
$\left(11\right)$ $3tan^{2}θ+2=3$ 
$\left(111\right)cos^{2}θ$ $11rac\left(1\right)\left(4\right)\right)=$ 
$c\left(1\right)\left(4\right)\right)=11113c\left(1\right)\left(2\right)\right)$ 

Which of the following rational numbers are 
equivalent? 
$0Ptionsy$ 
A \frac{5}{6}, \frac{30}{36} 
B $s\sqrt{rac\left(} -2\right)\left(3\right)\sqrt{1rac} \sqrt{4\right)16\right)4} $ 
C $s\sqrt{11aC\left(} -4\right)1-7b,\sqrt{1rac\left(16\sqrt{35\right)9} } $ 
D \frac{1}{2},\frac{3}{8} 

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