Calculate the value

$A.$ Simplify the following. 
$10$ $\sqrt [4] {625} $ $=$ 
$2$ $\sqrt [10] {625} =$ $\sqrt [6] {8m^{9}n^{12}} $ 
$3$ $-$ $-$ 

Plzz i need help, i need to pass this in less than 1 hour

$17$ $S$ Simplify $\sqrt [4] {625x^{28}y^{32}} $ 

Simplify the radical expression 
1. $\sqrt{63} $ 6. $\sqrt [3] {81} $ 
$2.$ $\sqrt{48} $ $7$ $\sqrt [3] {128} $ 
$3$ $\sqrt{75} $ $8.$ $\sqrt [4] {625} $ 
$4$ $\sqrt{99} $ $9$ $\sqrt [5] {96} $ 
$5$ $\sqrt [3] {24} $ $10$ $\sqrt [16] {128} $ 

$7.$ $\sqrt{16} =$ 
8. V49a b10 -= 
$9$ $\sqrt [4] {625} =$ 
$10.$ $\sqrt [3] {24} =$ 
$11.\sqrt [3] {64} =$ 
$6$ $\sqrt [3] {27a^{3}b6} =3ab^{2}$ $12$ $\sqrt [3] {8a^{5}b^{10}} =$ 

$\sqrt [4] {625} $ 
$11$ $-$ $\sqrt [5] {9} 6$ 
$7.$ $-$ $\sqrt [3] {8} 1$ $12$ $\sqrt [6] {128} $ 
$8.\sqrt [3] {128} $ $13$ $\sqrt [4] {-} $ $243$ 
$9,$ $3$ $\sqrt [3] {40} $ $14$ $\sqrt [3] {3000} $ 
$1O$ $\sqrt [3] {135} $ $15$ 

$\sqrt [4] {625} $ 
$11$ 2/96 
$7.\sqrt [3] {81} $ $12$ $\sqrt [6] {128} $ 
$8,\sqrt [3] {128} $ $13$ $4\sqrt{24} 3$ 
$9,$ $\sqrt [3] {40} $ $14$ $\sqrt [3] {3000} $ 
$1O$ $\sqrt [3] {135} $ $15$ 

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