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Solve the equation
Answer
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$y = - \left ( 7 - 2 x \right ) - 3 \left ( 9 - 5 x \right )$
$y = 0$
$x$Intercept
$\left ( 2 , 0 \right )$
$y$Intercept
$\left ( 0 , - 34 \right )$
$- \left( 7-2x \right) -3 \left( 9-5x \right) = 0$
$x = 2$
$ $ Solve a solution to $ x$
$- \left ( 7 - 2 x \right ) \color{#FF6800}{ - } \color{#FF6800}{ 3 } \left ( \color{#FF6800}{ 9 } \color{#FF6800}{ - } \color{#FF6800}{ 5 } \color{#FF6800}{ x } \right ) = 0$
$ $ Multiply each term in parentheses by $ - 3$
$- \left ( 7 - 2 x \right ) \color{#FF6800}{ - } \color{#FF6800}{ 3 } \color{#FF6800}{ \times } \color{#FF6800}{ 9 } \color{#FF6800}{ - } \color{#FF6800}{ 3 } \color{#FF6800}{ \times } \left ( \color{#FF6800}{ - } \color{#FF6800}{ 5 } \right ) \color{#FF6800}{ x } = 0$
$\color{#FF6800}{ - } \left ( \color{#FF6800}{ 7 } \color{#FF6800}{ - } \color{#FF6800}{ 2 } \color{#FF6800}{ x } \right ) - 3 \times 9 - 3 \times \left ( - 5 \right ) x = 0$
$ $ Change the symbol of each term in parentheses when there is a (-) symbol in front of parentheses $ $
$\color{#FF6800}{ - } \color{#FF6800}{ 7 } + \color{#FF6800}{ 2 } \color{#FF6800}{ x } - 3 \times 9 - 3 \times \left ( - 5 \right ) x = 0$
$- 7 + 2 x \color{#FF6800}{ - } \color{#FF6800}{ 3 } \color{#FF6800}{ \times } \color{#FF6800}{ 9 } - 3 \times \left ( - 5 \right ) x = 0$
$ $ Multiply $ - 3 $ and $ 9$
$- 7 + 2 x \color{#FF6800}{ - } \color{#FF6800}{ 27 } - 3 \times \left ( - 5 \right ) x = 0$
$- 7 + 2 x - 27 \color{#FF6800}{ - } \color{#FF6800}{ 3 } \color{#FF6800}{ \times } \left ( \color{#FF6800}{ - } \color{#FF6800}{ 5 } \right ) \color{#FF6800}{ x } = 0$
$ $ Simplify the expression $ $
$- 7 + 2 x - 27 + \color{#FF6800}{ 15 } \color{#FF6800}{ x } = 0$
$\color{#FF6800}{ - } \color{#FF6800}{ 7 } + 2 x \color{#FF6800}{ - } \color{#FF6800}{ 27 } + 15 x = 0$
$ $ Find the sum of the negative numbers $ $
$\color{#FF6800}{ - } \color{#FF6800}{ 34 } + 2 x + 15 x = 0$
$- 34 + \color{#FF6800}{ 2 } \color{#FF6800}{ x } \color{#FF6800}{ + } \color{#FF6800}{ 15 } \color{#FF6800}{ x } = 0$
$ $ Calculate between similar terms $ $
$- 34 + \color{#FF6800}{ 17 } \color{#FF6800}{ x } = 0$
$\color{#FF6800}{ - } \color{#FF6800}{ 34 } \color{#FF6800}{ + } \color{#FF6800}{ 17 } \color{#FF6800}{ x } = 0$
$ $ Organize the expression $ $
$\color{#FF6800}{ 17 } \color{#FF6800}{ x } \color{#FF6800}{ - } \color{#FF6800}{ 34 } = 0$
$17 x \color{#FF6800}{ - } \color{#FF6800}{ 34 } = 0$
$ $ Move the constant to the right side and change the sign $ $
$17 x = \color{#FF6800}{ 34 }$
$\color{#FF6800}{ 17 } \color{#FF6800}{ x } = \color{#FF6800}{ 34 }$
$ $ Divide both sides by the same number $ $
$\color{#FF6800}{ x } = \color{#FF6800}{ 2 }$
$ $ 그래프 보기 $ $
Graph
Solution search results
search-thumbnail-If the sum of two consecutive 
numbers is $45$ and one number is $X$ 
.This statement in the form of 
equation $1s:$ 
$\left(1$ Point) $\right)$ 
$○5x+1$ $1eft\left(x+1$ $r1gnt\right)=45s$ 
$○sx+1ef\left(x+2$ $r1gnt\right)=145s$ 
$sx+1x=45s$
7th-9th grade
Algebra
search-thumbnail-$s|ef\left(-1n$ $\left($ }\right)^{50}\ $\right)$ \ | | is\ equal\ to\ $S$ 
$s1S$ 
$S-1S$ 
$s2S$ 
$s50s$
7th-9th grade
Other
search-thumbnail-Given the set of ordered pairs $\left(\left(-7.0\right),\left(-6,5\right),\left(-5,-3\right),\left(-1,2\right)$ $\left(1,6\right),\left(2,-2\right)$ $\left(5,3\right)\left(7,-8\right)\right)$ 
Find f(7)fAleft(7\right) 
O a 
O b -8 
6. 
$5$
7th-9th grade
Algebra
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