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What is the inverse of $g\left(x\right)=\sqrt{x-1} $ 
$Og\left(x\right)=\sqrt{x+1} $ 
$+1$ $g^{'}\left(x\right)=5-$ $y_{9}$ $g\sqrt{ef\left(x\left(nght\right)} =\left(f_{tac\left(x+1\right)0sq\pi \left(x\right)}$ 
$Og^{'}\left(x\right)=x^{2}+1$ 
$○g\left(x\right)=x^{2}-1$ 
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$3$ $\left(\dfrac {2} {3}\longdiv{}5\times \left(\dfrac {5} {7}\longdiv{}5$ is equal to : 
$\left(\dfrac {2} {3}\longdiv{}5\times \left(\dfrac {5} {7}\longdiv{}5$ 
$\left(a$ $\left(\dfrac {2} {3}\times \dfrac {5} {7}\right)=10$ $\left(b\right)$ $\left(\dfrac {2} {3}\times \dfrac {5} {7}\longdiv{}5$ 
$tc\right)$ $\left(\dfrac {2} {3}\times \dfrac {5} {7}\right)^{25}$ $1$ (d) $\right)$ $\left(\dfrac {2} {3}\times \dfrac {5} {7}\longdiv{}25$ 

The rationalizing factor of \sqrt{23} is 
$°$ $Options^{°}$ $0$ 
A 24 
23 
C \sqrt{23} 
D None of these 

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