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Square root
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Find the approximate value
Answer
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$2 \sqrt{ 15 }$
Find the square root
$\sqrt{ \color{#FF6800}{ 60 } }$
$ $ Do a factorization in prime factors for the integral number inside the radical sign $ $
$\sqrt{ \color{#FF6800}{ 2 } ^ { \color{#FF6800}{ 2 } } \color{#FF6800}{ \times } \color{#FF6800}{ 3 } \color{#FF6800}{ \times } \color{#FF6800}{ 5 } }$
$\sqrt{ \color{#FF6800}{ 2 } ^ { \color{#FF6800}{ 2 } } \times 3 \times 5 }$
$ $ Separate the part that can be taken out of radical sign to different radical sign from the prime factor to the prime factor $ $
$\sqrt{ \color{#FF6800}{ 2 } ^ { \color{#FF6800}{ 2 } } } \sqrt{ 3 \times 5 }$
$\sqrt{ \color{#FF6800}{ 2 } ^ { \color{#FF6800}{ 2 } } } \sqrt{ 3 \times 5 }$
$ $ Get rid of the radical sign and change it to the denominator of the exponent $ $
$\color{#FF6800}{ 2 } ^ { \color{#FF6800}{ \frac { \color{#FF6800}{ 2 } } { \color{#FF6800}{ 2 } } } } \sqrt{ 3 \times 5 }$
$2 ^ { \color{#FF6800}{ \frac { \color{#FF6800}{ 2 } } { \color{#FF6800}{ 2 } } } } \sqrt{ 3 \times 5 }$
$ $ Reduce the fraction to the lowest term $ $
$2 ^ { \color{#FF6800}{ 1 } } \sqrt{ 3 \times 5 }$
$2 ^ { \color{#FF6800}{ 1 } } \sqrt{ 3 \times 5 }$
$ $ If the exponent is 1, get rid of it as it is unnecessary $ $
$2 \sqrt{ 3 \times 5 }$
$2 \sqrt{ \color{#FF6800}{ 3 } \color{#FF6800}{ \times } \color{#FF6800}{ 5 } }$
$ $ Multiply $ 3 $ and $ 5$
$2 \sqrt{ \color{#FF6800}{ 15 } }$
$\approx 7.746$
Find the approximate value
$\sqrt{ \color{#FF6800}{ 60 } }$
$ $ Find the approximate value of the square root $ $
$\approx \color{#FF6800}{ 7.746 }$
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