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Formula
Calculate the value
Answer
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$\sqrt{ 6 } \times \sqrt{ 12 } - \sqrt{ 24 } \div \sqrt{ 3 }$
$4 \sqrt{ 2 }$
Calculate the value
$\sqrt{ \color{#FF6800}{ 6 } } \sqrt{ \color{#FF6800}{ 12 } } - \sqrt{ 24 } \div \sqrt{ 3 }$
$ $ Calculate multiplication of root $ $
$\color{#FF6800}{ 6 } \sqrt{ \color{#FF6800}{ 2 } } - \sqrt{ 24 } \div \sqrt{ 3 }$
$6 \sqrt{ 2 } \color{#FF6800}{ - } \sqrt{ \color{#FF6800}{ 24 } } \color{#FF6800}{ \div } \sqrt{ \color{#FF6800}{ 3 } }$
$ $ Calculate the value that contains root $ $
$6 \sqrt{ 2 } \color{#FF6800}{ - } \color{#FF6800}{ \dfrac { \left ( 2 \sqrt{ 6 } \right ) \sqrt{ 3 } } { 3 } }$
$6 \sqrt{ 2 } - \dfrac { \left ( \color{#FF6800}{ 2 } \sqrt{ \color{#FF6800}{ 6 } } \right ) \sqrt{ \color{#FF6800}{ 3 } } } { 3 }$
$ $ Get rid of unnecessary parentheses $ $
$6 \sqrt{ 2 } - \dfrac { \color{#FF6800}{ 2 } \sqrt{ \color{#FF6800}{ 6 } } \sqrt{ \color{#FF6800}{ 3 } } } { 3 }$
$6 \sqrt{ 2 } - \dfrac { \color{#FF6800}{ 2 } \sqrt{ \color{#FF6800}{ 6 } } \sqrt{ \color{#FF6800}{ 3 } } } { 3 }$
$ $ Simplify the expression $ $
$6 \sqrt{ 2 } - \dfrac { \color{#FF6800}{ 6 } \sqrt{ \color{#FF6800}{ 2 } } } { 3 }$
$6 \sqrt{ 2 } - \color{#FF6800}{ \dfrac { 6 \sqrt{ 2 } } { 3 } }$
$ $ Reduce the fraction $ $
$6 \sqrt{ 2 } - \left ( \color{#FF6800}{ 2 } \sqrt{ \color{#FF6800}{ 2 } } \right )$
$6 \sqrt{ 2 } \color{#FF6800}{ - } \left ( \color{#FF6800}{ 2 } \sqrt{ \color{#FF6800}{ 2 } } \right )$
$ $ Get rid of unnecessary parentheses $ $
$6 \sqrt{ 2 } \color{#FF6800}{ - } \color{#FF6800}{ 2 } \sqrt{ \color{#FF6800}{ 2 } }$
$\color{#FF6800}{ 6 } \sqrt{ \color{#FF6800}{ 2 } } \color{#FF6800}{ - } \color{#FF6800}{ 2 } \sqrt{ \color{#FF6800}{ 2 } }$
$ $ Calculate between similar terms $ $
$\color{#FF6800}{ 4 } \sqrt{ \color{#FF6800}{ 2 } }$
Solution search results
search-thumbnail-$\left(2\dfrac {2} {3}$ $-1\dfrac {5} {6}\right)$ of $1$ $\dfrac {7} {12}-\left(\dfrac {7} {2}- \begin{cases} - \\ 8-\left(5\dfrac {1} {3}-3-2\dfrac {1} {2}\right) \end{cases} $
7th-9th grade
Calculus
search-thumbnail-The rationalizing factor of \sqrt{23} is 
$°$ $Options^{°}$ $0$ 
A 24 
23 
C \sqrt{23} 
D None of these
7th-9th grade
Other
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