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Formula
Calculate the value
Answer
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$\sqrt{ 3i \times - \sqrt{ 3i } }$
$\sqrt{ 3 i \sqrt{ 3 i } } i$
Calculate the value
$\sqrt{ 3 i \times \left ( \color{#FF6800}{ - } \sqrt{ 3 i } \right ) }$
$ $ Move the (-) sign forward $ $
$\sqrt{ \color{#FF6800}{ - } 3 i \sqrt{ 3 i } }$
$\sqrt{ \color{#FF6800}{ - } 3 i \sqrt{ 3 i } }$
$ $ Subtracting (-) from the square root gives i $ $
$\sqrt{ 3 i \sqrt{ 3 i } } \color{#FF6800}{ i }$
Solution search results
search-thumbnail-$\left(\dfrac {1-\sqrt{3i} } {1+\sqrt{3i} }$ $5$
1st-6th grade
Algebra
Check solution
search-thumbnail-What is the inverse of $g\left(x\right)=\sqrt{x-1} $ $Og\left(x\right)=\sqrt{x+1} $ $+1$ $g^{'}\left(x\right)=5-$ $y_{9}$ $g\sqrt{ef\left(x\left(nght\right)} =\left(f_{tac\left(x+1\right)0sq\pi \left(x\right)}$ $Og^{'}\left(x\right)=x^{2}+1$ $○g\left(x\right)=x^{2}-1$ « Previous Ne
Other
Check solution
search-thumbnail-What is the inverse of $g\left(x\right)=\sqrt{x-1} $ $Og\left(x\right)=\sqrt{x+1} $ $+1$ $g^{'}\left(x\right)=5-$ $y_{9}$ $g\sqrt{ef\left(x\left(nght\right)} =\left(f_{tac\left(x+1\right)0sq\pi \left(x\right)}$ $Og^{'}\left(x\right)=x^{2}+1$ $○g\left(x\right)=x^{2}-1$ « Previous Ne
Other
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search-thumbnail-$-\dfrac {1} {2}+\dfrac {\sqrt{3i} } {2}$ $3$
1st-6th grade
Other
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search-thumbnail-The rationalizing factor of \sqrt{23} is $°$ $Options^{°}$ $0$ A 24 23 C \sqrt{23} D None of these
7th-9th grade
Other
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