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Formula
Calculate the value
Answer
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$\sqrt{ 27 } \times \sqrt{ 8 } \div \sqrt{ 12 }$
$3 \sqrt{ 2 }$
Calculate the value
$\sqrt{ \color{#FF6800}{ 27 } } \sqrt{ \color{#FF6800}{ 8 } } \color{#FF6800}{ \div } \sqrt{ \color{#FF6800}{ 12 } }$
$ $ Calculate the value that contains root $ $
$\color{#FF6800}{ 3 } \sqrt{ \color{#FF6800}{ 2 } }$
Solution search results
search-thumbnail-$\left(1y\right)$ $\left(\dfrac {3} {8}\longdiv{}8\times \left(\dfrac {6} {4}\longdiv{}5+\left(\dfrac {16} {24}\right)^{3}$ $\left(y\right)$ $\left(\left(\dfrac {2} {9}\longdiv{}8$ $\longdiv{}2$ $\times $ $\left(\left(\dfrac {4} {27}\longdiv{}4\right)$ $=3$ $1-1$ $\left(yi\right)$ $\left(\dfrac {4} {15}\longdiv{}^{5}\times \left(\dfrac {25} {8}\longdiv{}8$ $+\left(\dfrac {5} {18}\longdiv{}6$
7th-9th grade
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search-thumbnail-What is the inverse of $g\left(x\right)=\sqrt{x-1} $ $Og\left(x\right)=\sqrt{x+1} $ $+1$ $g^{'}\left(x\right)=5-$ $y_{9}$ $g\sqrt{ef\left(x\left(nght\right)} =\left(f_{tac\left(x+1\right)0sq\pi \left(x\right)}$ $Og^{'}\left(x\right)=x^{2}+1$ $○g\left(x\right)=x^{2}-1$ « Previous Ne
Other
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search-thumbnail-What is the inverse of $g\left(x\right)=\sqrt{x-1} $ $Og\left(x\right)=\sqrt{x+1} $ $+1$ $g^{'}\left(x\right)=5-$ $y_{9}$ $g\sqrt{ef\left(x\left(nght\right)} =\left(f_{tac\left(x+1\right)0sq\pi \left(x\right)}$ $Og^{'}\left(x\right)=x^{2}+1$ $○g\left(x\right)=x^{2}-1$ « Previous Ne
Other
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search-thumbnail-The rationalizing factor of \sqrt{23} is $°$ $Options^{°}$ $0$ A 24 23 C \sqrt{23} D None of these
7th-9th grade
Other
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