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Square root
Answer
$16$
Find the square root
$\sqrt{ \color{#FF6800}{ 256 } }$
$ $ Do a factorization in prime factors for the integral number inside the radical sign $ $
$\sqrt{ \color{#FF6800}{ 2 } ^ { \color{#FF6800}{ 8 } } }$
$\sqrt{ \color{#FF6800}{ 2 } ^ { \color{#FF6800}{ 8 } } }$
$ $ Get rid of the radical sign and change it to the denominator of the exponent $ $
$\color{#FF6800}{ 2 } ^ { \color{#FF6800}{ \frac { \color{#FF6800}{ 8 } } { \color{#FF6800}{ 2 } } } }$
$2 ^ { \color{#FF6800}{ \frac { \color{#FF6800}{ 8 } } { \color{#FF6800}{ 2 } } } }$
$ $ Reduce the fraction to the lowest term $ $
$2 ^ { \color{#FF6800}{ 4 } }$
$\color{#FF6800}{ 2 } ^ { \color{#FF6800}{ 4 } }$
$ $ Calculate power $ $
$\color{#FF6800}{ 16 }$
Solution search results
The rationalizing factor of \sqrt{23} is
$°$ $Options^{°}$ $0$
A 24
23
C \sqrt{23}
D None of these
7th-9th grade
Other
Search count: 722
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