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Formula
Square root
Answer
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$\sqrt{ 1369 }$
$37$
Find the square root
$\sqrt{ \color{#FF6800}{ 1369 } }$
$ $ Do a factorization in prime factors for the integral number inside the radical sign $ $
$\sqrt{ \color{#FF6800}{ 37 } ^ { \color{#FF6800}{ 2 } } }$
$\sqrt{ \color{#FF6800}{ 37 } ^ { \color{#FF6800}{ 2 } } }$
$ $ Get rid of the radical sign and change it to the denominator of the exponent $ $
$\color{#FF6800}{ 37 } ^ { \color{#FF6800}{ \frac { 2 } { 2 } } }$
$37 ^ { \color{#FF6800}{ \frac { 2 } { 2 } } }$
$ $ Reduce the fraction to the lowest term $ $
$37 ^ { \color{#FF6800}{ 1 } }$
$37 ^ { \color{#FF6800}{ 1 } }$
$ $ If the exponent is 1, get rid of it as it is unnecessary $ $
$37$
Solution search results
search-thumbnail-$10$ Find $x$ if $\sqrt{1369} +\sqrt{0.0615+x} =37.25$
7th-9th grade
Algebra
search-thumbnail-$Q5$ $\sqrt{1369} -37$ find the value of $\sqrt{0.1369} +\sqrt{136900} $
7th-9th grade
Other
search-thumbnail-$Q5$ $\sqrt{1369} -37$ find the value of $\sqrt{0.1369} +\sqrt{136900} $
7th-9th grade
Other
search-thumbnail-The rationalizing factor of \sqrt{23} is 
$°$ $Options^{°}$ $0$ 
A 24 
23 
C \sqrt{23} 
D None of these
7th-9th grade
Other
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